The graph of a linear equation may not be a straight line.

Answers

Answer 1
Answer: If this is a true false question. The answer is false. The idea behind a linear equation is that it is a straight line. Proof for this is the y=mx+b equation. Where m defines a constant slope(or in other words, a straight line) and b represents how high the line appears.
As you can see there is nothing that could bend the line into a more curvy shape (things that do bend are polynomials and such)

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Solve for a: a2-8a+12 which is the correct a.-2,-6 b.2,6. C.-3,-4 or d.3,4 for me is Ccc help pleas

Answers

a^2-8a+12 =0 \n \n(a-2)(a-6)=0 \n \na-2=0 \ \ or \ \ a-6 =0 \n \na=2 \ \ or \ \ a=6 \n \nAnswer : \ b. \ \ 2,6


If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?(2, 1)
(1, 1)
(0, 1)

Answers

Answer:

(1, 1)

Step-by-step explanation:

Since, the equation of the line with slope m and passes through (x_1, y_1) is,

y-y_1=m(x-x_1)

Here,

x_1=0, y_1 = -1, m = 2

Thus, the equation of the line,

y + 1 = 2(x-0)

⇒ y + 1 = 2x

If a point lies on the line then it must satisfy the equation of the line,

For (2, 1)

1 + 1 ≠ 2(2)

For (1, 1)

1 + 1 = 2(1)

For (0, 1)

1 + 1 ≠ 2(0)

Thus, the point (1, 1) lies on the line.

the slope is 2/1, So the rise is 2 and the run is 1. So, (1,1) is on the line

H = vt - 16t^2, solve for v

Answers

The equation h = vt - 16t² is solved for v will be given as v = (h + 16t²) / t.

What is the solution to the equation?

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

Making anything easier to accomplish or comprehend, as well as making it lessdifficult, is the definition of simplification.

The equation is given below.

h = vt - 16t²

Simplify the equation for v, then the equation is written as,

h = vt - 16t²

vt = h + 16t²

v = (h + 16t²) / t

The equation h = vt - 16t² is solved for v will be given as v = (h + 16t²) / t.

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ2

H=vt-16t²
vt-16t²=H
vt=16t²+H
v=(16t²+H)/t
v=16(t²/t)+H/t
v=16t+H/t

Answer: the answer would be: v=16t+H/t

How to solve this one​

Answers

Answer:

Step-by-step explanation:

w^3 + 4w^2 + 5w - 12

I WILL ANSWER SO TIMMY GET CROWN

When e = 4, f = 2, and g = 8. If e varies jointly with f and g, what is the constant of variation?

Answers

Answer:

The\ constant\ of\ variation\ is\ (1)/(4).

Step-by-step explanation:

As given in the question

If e varies jointly with f and g.

i.e

e \propto fg

e = kfg

Where k is the constant of variation.

As

When e = 4, f = 2, and g = 8

Put in the above

4 = k × 2 × 8

4 = 16k

k = (4)/(16)

k = (1)/(4)

Therefore\ the\ constant\ of\ variation\ is\ (1)/(4).


in joint variation, the equation of variation holds the form 

e=k*fg, where k is the constant of variation. you can see how if either f or g increases, e increases as well, making e vary jointly with f and g. we are given the numbers e=4, f=2, and g=8, so when we input those into the general equations, 

4=k*2*8,
k=1/4

Find the common ratio of r 6,24,96,384

Answers

Each term is 4 times the previous one.