Help? Question are above. 15 points
Help? Question are above. 15 points - 1

Answers

Answer 1
Answer:

Answer:

1).

7, rational

2).

2.36 (repeating), irrational

3).

Simplify:(734)/(1000) / (2)/(2) = (367)/(500)

4).

Simplify: (2588)/(1000) /(4)/(4) =(647)/(250) \nIf.you.want.to.convert.it.to.a.mixed.fraction: 2(147)/(250)


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Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = −sin x, [0, π] Find all values of x in the interval for which the function equals its average value. (Enter your answers as a comma-separated list. Round your answers to three decimal places.)
For what value of c is the relation a function?
2) On a flight from New York to London, an airplane travels at a constant speed. An equation relating the distance traveled in miles, d, to the number of hours flying, t, is t= d. How long will it take the airplane to travel 800 miles? Show your work 500

Consider this composite figure that is made of two half spheres a cylinder. A composite figure is comprised of one cylinder and two half spheres. The cylinder has a height of 9 millimeters and radius of 5 millimeters. The volumes of each figure that make the composite figure have been determined. Sphere V = 500 3 π mm3 Cylinder V = 225π mm3 What is the volume of the composite figure?

Answers

Answer:

the answer is c

1,175/3mm3

Step-by-step explanation:

I got it right

Answer:

Actually:

V = 500/3

Find the range of each function for the given domain.
7. A(x) = 2;1-1.2,0,02,12,4

Answers

Final answer:

The range of the function A(x) = 2 is {2}.


Explanation:

The range of a function represents all the possible values that the function can output for the given inputs.
In this case, the function A(x) = 2 has a constant output of 2 for every input value in the domain.
Therefore, the range of this function is {2} as it only produces the output of 2.


Learn more about Range of a function here:

brainly.com/question/36487396


According to a survey conducted in a certain year by the Federal Communications Commission (FCC) of 3005 adults who were home broadband users, 34.5% of those surveyed had switched their service over the past 3 years. Of those who had switched service in the past 3 years, 51% were very satisfied, 39% were somewhat satisfied, and 10% were not satisfied with their service. Of the 65.5% who had not switched service in the past 3 years, 48% were very satisfied, 43% were somewhat satisfied, and 9% were not satisfied with their service.(a) What is the probability that a participant chosen at random had not switched service in the past 3 years and was very satisfied with their service?


(b) What is the probability that a participant chosen at random was not satisfied with their service?

Answers

Answer:

(a) The probability is 31.44%

(b) The probability is 9.345%

Step-by-step explanation:

The probability for part (a) is calculated as a multiplication of:

65.5% * 48% = 31.44%

Where 65.5% is the percentage of participants that had not switched service in the past 3 years and 48% are the percentage of those 65.5% that were very satisfy. So, the 31.44% of the participants had not switched service in the past 3 years and were very satisfied with their service.

Then, for part b, we have 2 cases:

  • Case 1: A person that had not had switched service in the past 3 years and was not satisfied with their service
  • Case 2:A person that had not switch in the past 3 years and was not satisfied with their service.

So, the probability is calculated as a sum of these two probabilities.

Therefore, the probability for case 1 is calculated as:

34.5% * 10% = 3.45%

Where 34.5% is the percentage of participants that had switched service in the past 3 years and 10% are the percentage of those 34.5% that were not satisfy.

At the same way, the probability for case 2 is:

65.5% * 9% = 5.895%

Finally, the probability that a participant chosen at random was not satisfied with their service is the sum of 3.45% and 5.895%. That is:

3.45% + 5.895% = 9.345%

Find the sum of 2x2 – 8x — 6 and 9x2 – 8.
Answer:
Submit Answer

Answers

Hence , the sum is 11x^2-8x-14.

WHAT IS A POLYNOMIAL

In mathematics, a polynomial is an expression consisting of indeterminates (also called variables) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

How to Solve?

Given , we need to add 2x^2-8x-6 and 9x^2-8.

So, we can write it as :

2x^2 -8x-6+9x^2-8

Writing like terms together:

= 2x^2+9x^2-8x-6-8

=11x^2-8x-14

Hence , the answer is 11x^2-8x-14.

Learn more about Algebraic expressions :

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#SPJ2

Answer:f

(x)=x,  g(x)=x3−1f(x)=x4+x3−11x2−5x+30,  g(x)=2x−2f(x)=x2,  g(x)=7x−1

in short ways the answer is  7x−1

Which lst of ordered pairs represents solutions to x+y= 2? (4.6), (0, 2), (4, 2) (4,6), (0, 2). (4, 2) (4,-6), (0, 2), (4, 2) ​

Answers

answer: x+y=2

0+2=²

( 0 , 2 )

Answer:

(0,2)

Step-by-step explanation:

0 + 2 = 2

Where x = 0, y = 2

Salmon Weights: Assume that the weights of spawning Chinook salmon in the Columbia river are normally distributed. You randomly catch and weigh 17 such salmon. The mean weight from your sample is 19.2pounds with a standard deviation of 4.4 pounds. You want to construct a 90% confidence interval for the mean weight of all spawning Chinook salmon in the Columbia River.(a) What is the point estimate for the mean weight of all spawning Chinook salmon in the Columbia River?
pounds

(b) Construct the 90% confidence interval for the mean weight of all spawning Chinook salmon in the Columbia River. Round your answers to 1 decimal place.
< ? <

(c) Are you 90% confident that the mean weight of all spawning Chinook salmon in the Columbia River is greater than 18 pounds and why?

No, because 18 is above the lower limit of the confidence interval.

Yes, because 18 is below the lower limit of the confidence interval.

No, because 18 is below the lower limit of the confidence interval.

Yes, because 18 is above the lower limit of the confidence interval.


(d) Recognizing the sample size is less than 30, why could we use the above method to find the confidence interval?

Because the sample size is greater than 10.

Because we do not know the distribution of the parent population.

Because the parent population is assumed to be normally distributed.

Because the sample size is less than 100.

Answers

Answer:

a) \bar X= 19.2 represent the sample mean. And that represent the best estimator for the population mean since \hat \mu =\bar X=19.2  b) The 90% confidence interval is given by (17.3;21.1)  

c) No, because 18 is above the lower limit of the confidence interval.

d) Because the parent population is assumed to be normally distributed.

The reason of this is because the t distribution is an special case of the normal distribution when the degrees of freedom increase.

Step-by-step explanation:

1) Notation and definitions  

n=17 represent the sample size

Part a  

\bar X= 19.2 represent the sample mean. And that represent the best estimator for the population mean since \hat \mu =\bar X=19.2  Part b

s=4.4 represent the sample standard deviation  

m represent the margin of error  

Confidence =90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

2) Calculate the critical value tc  

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. The degrees of freedom are given by:  

df=n-1=17-1=16  

We can find the critical values in excel using the following formulas:  

"=T.INV(0.05,16)" for t_(\alpha/2)=-1.75  

"=T.INV(1-0.05,16)" for t_(1-\alpha/2)=1.75  

The critical value tc=\pm 1.75  

3) Calculate the margin of error (m)  

The margin of error for the sample mean is given by this formula:  

m=t_c (s)/(√(n))  

m=1.75 (4.4)/(√(17))=1.868  

4) Calculate the confidence interval  

The interval for the mean is given by this formula:  

\bar X \pm t_(c) (s)/(√(n))  

And calculating the limits we got:  

19.2 - 1.75 (4.4)/(√(17))=17.332  

19.2 + 1.75 (4.4)/(√(17))=21.068  

The 90% confidence interval is given by (17.332;21.068)  and rounded would be:  (17.3;21.1)

Part c

No, because 18 is above the lower limit of the confidence interval.

Part d

Because the parent population is assumed to be normally distributed.

The reason of this is because the t distribution is an special case of the normal distribution when the degrees of freedom increase.