Answer:
A. h=3
Step-by-step explanation:
Step-by-step explanation:
soln
7h + 10 = 9h + 4
then you correct like terms together
9h - 7h = 10 - 4
2h = 6
2 2
h = 3
the is A
Answer:
Possible options:
= -4 * 3 1/4
= -4 * 13/4
= -4 * 3.25
Step-by-step explanation:
Without the options that seemed to go along with this question, it will be difficult to give the exact expression, but here are a few options.
-4 * 3 1/4 = -13
-4 * 13/4 = -13
-4 * 3.25 = -13
Each of these expressions will give the product of -4 and 3 1/4.
Cheers
(c) Give a function t = f −^1 (w) relating the time to the width of the surface of the water. Make sure to specify the domain and compute the range too.
Answer:
(a) Let h represents the height of water and w represents the width of the water,
Since, the depth of the water is increasing at a rate of 2 inches per hour,
So, after t hours,
The height of water, h(t) = 2t inches = t/6 ft,
( ∵ 1 foot = 12 inches ⇒ 1 inch = 1/12 ft )
Thus, the distance distance from the centre to the top of the water, d = 9 - h(t) ( see in the diagram )
,
By the Pythagoras theorem,
Since, diameter of the semicircular cross section is 18 ft,
So, 0 ≤ w ≤ 18,
i.e Range = [0, 18]
Also, w will be defined if 108t - t² ≥ 0
⇒ (108 - t)t ≥ 0,
⇒ 0 ≤ t ≤ 108
i.e Domain = [0, 108]
(b) If w = 6,
By using quadratic formula,
Hence, After 3.1 hours or 104.9 hours will the surface of the water have width of 6 feet.
(c)
For 0 ≤ w ≤ 18,
0 ≤ t ≤ 108,
So, Domain = [0, 18]
Range = [0, 108]
The width of the water's surface in a semicircular trough can be represented by the function w=t/3 and its domain is t ≥ 0 and the range is 0 ≤ w ≤ 6. To have a 6 feet wide surface, thus, it would take 18 hours. The inverse function is t=3w, with a domain of 0 ≤ w ≤ 6 and range of t ≥ 0.
Given that the depth of the water is increasing at a rate of 2 inches per hour in a semicircular trough, we can convert this rate to feet per hour by dividing by 12, getting an increase of 1/6 feet per hour.
(a) We can express the width of the surface of the water as a function of time. We consider the cross-section of the trough is a semicircle. So, the radius of the water's surface will be the height of water, and this height increases at 1/6 feet per hour. Therefore, the width of the surface of water, w=2r=2*1/6t=t/3. The domain of the function is t ≥ 0 and the range is 0 ≤ w ≤ 6.
(b) We set w=6 in the function w=t/3 and solve for t. We get t=3*6=18 hours.
(c) The inverse function of w=t/3 is t=3w. The domain of the inverse function is 0 ≤ w ≤ 6 and the range is t ≥ 0.
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Answer:
the first picture is 5.2 so b
The second picture is 2 and a half centimeters so also b
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Step-by-step explanation:
Answer:
The answers are A and C
Step-by-step explanation:
A is correct because -16 is on the left of the number line.
Answer:
942
Step-by-step explanation:
The formula for cone volume is V=πr²h/3. If you plug the radius and height in for the variables and use 3.14 for pi you get 942.