PHYSICS HIGH SCHOOL

A long solenoid has 1400 turns per meter of length, and it carries a current of 4.9 A. A small circular coil of wire is placed inside the solenoid with the normal to the coil oriented at an angle of 90.0˚ with respect to the axis of the solenoid. The coil consists of 42 turns, has an area of 1.2 × 10-3 m2, and carries a current of 0.45 A. Find the torque exerted on the coil.

Answers

Answer 1

Answer:

Answer:

The torque on the coil is $1.955* 10^(- 4)\ N-m$

Solution:

No. of turns per meter length, n = 1400 turns\m

Current, I = 4.9 A

Angle, $\theta = 90.0^(\circ)$

No. of turns of coil, N = 42 turns

Area, A = $1.2* 10^(- 3)m^(2)$

Current in the coil, I' = 0.45 A

Now,

To calculate the exerted torque on the coil:

The magnetic field, B produced inside the coil is given by:

$B = n\mu_(o)I$

$B = 1400* 4\pi times 10^(- 7)* 4.9 = 8.62* 10^(- 3)\ T$

Now, the torque exerted is given by:

$\tau = I'NAB$

$\tau = 0.45* 42* 1.2* 10^(- 3)* 8.62* 10^(- 3) = 1.955* 10^(- 4)\ N-m$

Answer 2

Answer:

Answer:

$T\approx 1.95* 10^(-4) N.m$

Explanation:

Given:

A long solenoid having

no. of turns per meter, n =1400

current, I = 4.9 A

A small coil of wire placed inside the solenoid

angle of orientation with respect to the axis of the solenoid, $\theta=90\degree$ °

no. of turns in the coil, N = 42

area of the coil, $a= 1.2* 10^(-3) m^2$

current in the coil, $i =0.45 A$

We have for torque:

$T=n.i.a.B. sin\theta$ .......................(1)

∵ $B=\mu_(0) .n.I$ ................................(2)

where:

B= magnetic field

$\mu_0=$ The permeability of free space = $4\pi*10^(-7) T.m.A^(-1)$

Substitute B from eq. (2) into eq. (1) we have:

$T=n.i.a.(\mu_0.N.I ).sin\theta$

putting the respective values in above eq.

$T=42* 0.45* 1.2* 10^(-3)* 4\pi*10^(-7) * 1400* 4.9* sin 90^(\circ)$

$T\approx 1.95* 10^(-4) N.m$

Related Questions

During a laboratory experiment, a student findsthat at 20° Celsius, a 6.0-meter length of copperwire has a resistance of 1.3 ohms. The crosssectionalarea of this wire is(1) 7.9 × 10^−8 m2 (3) 4.6 × 10^0 m2(2) 1.1 × 10^−7 m2 (4) 1.3 × 10^7 m2
A piece of wood and a piece of steel are at the same temperature; however, the steel feels hotter. This is because the steel has?
A weightless spring is stretched 10 cm by a suspended 1-kg block. If two such springs are used to suspend the block, one spring above the other, to effectively provide one double-length spring, then the total stretch of the double-length spring will be
You drop your backpack out of a window from a height of 8.3 m. What is the impact speed of your backpack?A. 163 m/s B. 1.2 m/s C. 21.3 m/s D. 12.8 m/s
Trumpeter A holds a B-flat note on the trumpet for a long time. Person C is running towards the trumpeter at a constant velocity. Person B is running away from the trumpeter at the same rate. Person D is standing still the whole time.Which person hears a frequency that is lower than the B-flat?A) Person A B) Person B C) Person C D) Person D

A police car is parked by the side of a highway and its siren emits a sound measuring 750 Hz. As you approach the police car from a distance, you hear a change in the sound. The change is in the sound's

Answers

As you approach the police car with blaring siren, you hear a change in pitch and frequency. The apparent pitch changes as a result of the Doppler effect. Frequency determines pitch; frequency and wavelength are inversely proportional. You wouldn't "hear" either one. The result is pitch.

D) pitch and frequency.

Answer:

The correct answer would be frequency, intensity, and amplitude.

It can be explained with the help of Doppler effects which states that the frequency or wavelength of sound changes (increases or decreases) as source and observer move towards or away from each other.

Due to this effect, the frequency and intensity of siren increase as we move towards the siren.

In addition, amplitude also increases as we move towards the source of the sound and decreases as the observer moves away from the source.

if a wave has a velocity of 24 m/s and a period of 3.0 s. what is he frequency of the wave in Hz?

Answers

The frequency doesn't depend on the wave speed.
Frequency is simply the reciprocal of the period.

Frequency= 1 / (3sec) = 1/3 per sec = 1/3 Hz.

We know that by definition Frequency is the reciprocal of period.
So
f=1/3=0.33Hz

What would be the meaning of a nonzero y intercept to a graph of total mass versus volume?

Answers

It would imply the object has some volume but 0 mass which isn't possible. Negligible masses with volumes can be considered however absolutely 0 mass really means the object doesn't exist at all. Thus, showing the graph is wrong.

Two identical freight cars roll without friction (one at 1 m/s, the other at 2 m/s) toward each other on a level track. They collide, couple together, and roll away in the direction that _________.

Answers

Answer:

They collide, couple together, and roll away in the direction thatthe 2m/s car was rolling in.

Explanation:

We should start off with stating that the conservation of momentum is used here.

Momentum = mass * speed

Since, mass of both freight cars is the same, the speed determines which has more momentum.

Thus, the momentum of the 2 m/s freight car is twice that of the 1 m/s freight car.

The final speed is calculated as below:

mass * (velocity of first freight car) + mass * (velocity of second freight car) = (mass of both freight cars) * final velocity

(m * V1) + (m * V2) = (2m * V)

Let's substitute the velocities 1m/s for the first car, and - 2m/s for the second. (since the second is opposite in direction)

We get:

$m*1 + m*(-2) = 2m*V$

solving this we get:

V = - 0.5 m/s

Thus we can see that both cars will roll away in the direction that the 2 m/s car was going in. (because of the negative sign in the answer)

Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 13 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 22 cm such that the combination does not rotate?

Answers

Answer:

$F_2 = 29.54 N$

Explanation:

As we know that the combination is maintained at rest position

So we will take net torque on the system to be ZERO

so we know that

$\tau = \vec r * \vec F$

here we will have

$\vec r_1 * F_1 = \vec r_2 * F_2$

so we have

$13 * 50 = 22 * F_2$

so we have

$F_2 = (13 * 50)/(22)$

$F_2 = 29.54 N$

Final answer:

The concept of torques and equilibrium is used to calculate the pulling force on the larger flywheel, which is found to be approximately 29.55 Newtons. This force will balance the system and prevent it from rotating.

Explanation:

To solve this problem, we need to understand the concept of torque and equilibrium. We know that torque (τ) is the rotational equivalent of linear force. It's calculated by the formula τ = force × radius. Thus, for the system to stay at equilibrium (not rotate), the torques need to balance each other out.

On the smaller flywheel, the torque τ₁ is given by the pulling force (F₁ = 50 N) and the radius (r₁ = 13 cm, or 0.13 m), hence τ₁ = F₁ × r₁ = 50 N x 0.13 m = 6.5 N.m.

In order for the system to stay at equilibrium, the same amount of torque needs to be applied to the larger flywheel. We already know the radius of the larger flywheel (r₂ = 22 cm, or 0.22 m). To keep the system at equilibrium, the pulling force F₂ on the larger flywheel should be such that the torque τ₂ = τ₁ = 6.5 N.m. From the formula τ = F × r, we can solve for F₂ as follows: F₂ = τ₂ / r₂ = 6.5 N.m / 0.22 m = 29.55 N, approximately. Therefore, a pulling force of about 29.55 N should be applied to the cord connected to the larger flywheel to prevent the system from rotating.

Learn more about Torques and Equilibrium here:

brainly.com/question/34217227

#SPJ3

Solve the problem.The Bay area of California was shaken by an earthquake on October 17, 1989. The epicenter was located at Loma Prieta. The diameter of the earthquake's horizontal waves that shocked the area measured about 120 miles. How many square miles were affected by this earthquake?

Answers

As the shock waves travel in concentric outward circles from the epicenter, and the diameter is measured 120 miles,
area of a circle =πr*r

d=120
r=120/2r=6060*60=36003600*π=11309.734
11309.734 square miles

Other Questions

The Greeks rejected the notion that the Earth orbits the Sun. Why? A.) They believed that the Sun is a God.B.) They weren't as smart as we are. C.) They could not measure a change in stars' positions on the sky. D.) They could not measure how big the Earth was.

A ball is thrown horizontally from the top ofa building 140 m high. The ball strikes the ground 54 m horizontally from the point of release. What is the speed of the ball just before it strikes the ground? Answer in units of m/s.

Calculate the volume of this regular solid.A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.

What is the name of the process that describes the decrease in frequency