Answer:
Factor:
9x2 – 64
=(3x+8)(3x−8)
3x – 8
A. Divide 8x^3 by 2x.
B. Divide 2x by 8x^3.
C. Divide 6x by 2x.
D. Divide 2x by 6x.
B. 8.9 in.
C. 10 in.
D. 9.1 in.
Answer:
x2 = 8.1 in (Option A)
Step-by-step explanation:
Given:-
- The extension of spring x1 = 9 in
- The weight hanged F1 = 100 lbs
Find:-
How far will it stretch with 90 pounds attached?
Solution:-
- The linear extension x of spring is proportional to the amount of force F applied to the spring.
F = k*x
Where, k = is the proportionality constant called stiffness of the spring.
- We will first determine the spring stiffness k using the given data as follows:
F1 = k*x1
100 = k*9
k = 100 / 9
- Now, we will determine the amount with which the spring stretches x2 when the hanged weight is changed to F2 = 90 lbs. Using the first relation we plug in the value of proportionality constant (stiffness) k.
F = (100 / 9)*x
F2 = (100 / 9)*x2
90 = (100 / 9)*x2
x2 = 810 / 100
x2 = 8.1 in
- The amount of spring stretches when the applied load of weight hanged is changed to F2 = 90 lbs is x2 = 8.1 in.
Answer: vertex: (1,-9); intercepts: x=4,-2
Step-by-step explanation:
Just got it wrong on ap3x so I could give y’all the right answer
A)4x^3
B)4x^5y
C)8x^5
D)112x^5y