Whats the total area of a covered box with a length of 4 ft, a width of 3 ft, and a height of 6 ft
Answers
The total area of the covered box is 108 square feet.
We have the specifications of the box -
length (L) = 4 ft
width (B) = 3 ft
height (H) = 6 ft
We have to find the total area of the box.
What is the formula to calculate the total surface area of a cuboid ?
The total surface area will be -
A = 2(LB + BH + LH)
Using the formula above, we get -
A = 2(4 x 3 + 3 x 6 + 4 x 6)
A = 2(12 + 18 + 24)
A = 2 x 54
A = 108 square feet
Hence, the total area of the covered box is 108 square feet.
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The top and bottom will be 4 x 3 = 12 sq ft.
2 sides each 4 x 6 = 24 x 2 = 48 sq ft.
2 sides each 3 x 6 = 18 x 2 = 36 sq ft.
Area = 24 + 36 + 48 sq ft = 108 sq ft.
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multiply or divide the top bottom numbers by the same number
1 M= 1/3 B= 7
2 M= -3 B= -7
3 M= 3 B= -7
4 M= -1/3 B= 7
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Answer:
3 M= 3 B=-7
Step-by-step explanation:
Answer:
Answer is 3
3 M= 3 B= -7
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In this case, the triangle will be an isosceles triangle because two sides have the same length (3) and the other side is different (4).
Hope this helps :)
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x(x^2 + 4) - 4(x^2 + 4) = 0
x^3 + 4x - 4x^2 - 16 = 0
x^3 - 4x^2 + 4x - 16 = 0