If 40% is equal to the fraction of x by 30 what is the value of x

Answers

Answer 1
Answer: Given
  40% = x/30
multiply by 30
  30·0.40 = x = 12

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Solve the algebraic expression n + 8, if n = 15

Answers

you mean evaluate

n+8
if n=15
15+8=
10+5+8=
10+3+2+8=
13+10=
23
plug in 15 so n+8 ...15+8=23

If on a scale drawing 100 feet are represented by 15 inches, then a scale of 1/2 inches represents how many feet

Answers

Answer:

3(1)/(3) feet

Step-by-step explanation:

Inches : Feet = 15 : 100

Let 'x' be the feet required to find

15 : 100 :: 1/2 : x

Product of extremes  = product of means

          15 * x = 100 * (1/2)

          15 * x = 50

                  x = 50/15

                 x  =  10/3

                 x = 3(1)/(3)

                 

Answer:

3 1/3 feet

Step-by-step explanation:

100 feet : 15 inches

3 1/3 feet : 1/2 inch

The hypotenuse of the triangle shown below is 12 inches. What is the lengthof a side in inches?

Answers

Can you send a picture of the triangle ?

Find the midpoint of the segment with these endpoint (4,6),(9,3)​

Answers

Answer:

The midpoint of the segment is (6, 4.5).

Step-by-step explanation:

Midpoint of a segment:

The midpoint of a segment is given by the mean of the coordinates of their endpoints.

Segment with coordinates (3,6) and (9,3).

Mean x-coordinate: (3+9)/2 = 12/2 = 6

Mean y-coordinate: (6+3)/2 = 9/2 = 4.5

The midpoint of the segment is (6, 4.5).

We must use substitution to do this second integral. We can use the substitution t = 7x, which will give dx = Correct: Your answer is correct. dt. Ignoring the constant of integration, we have sin(7x) dx =

Answers

Answer:

Therefore, the solution is:

\boxed{\int \sin 7x\, dx=-(\cos 7x)/(7)}

Step-by-step explanation:

We calculate the given integral.  We use the substitution t = 7x.

\int \sin 7x\, dx=\begin{vmatrix} 7x=t\n 7\, dx=dt\n dx=(dt)/(7) \end{vmatrix}\n\n=\int \sin t \cdot (1)/(7)\, dt\n\n=(1)/(7)\cdot (-\cos t)\n\n=-(\cos 7x)/(7)

Therefore, the solution is:

\boxed{\int \sin 7x\, dx=-(\cos 7x)/(7)}

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. The numbers y of cell sites from 1985 through 2011 can be modeled byy = 269573/1+985e^-0.308t where t represents the year, with t = 5 corresponding to 1985. Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006.

Answers

Answer:

(a) 3178

(b) 14231

(c) 33152

Step-by-step explanation:

Given

y = (269573)/(1+985e^(-0.308t))

Solving (a): Year = 1998

1998 means t = 8 i.e. 1998 - 1990

So:

y = (269573)/(1+985e^(-0.308*8))

y = (269573)/(1+985e^(-2.464))

y = (269573)/(1+985*0.08509)

y = (269573)/(84.81365)

y = 3178 --- approximated

Solving (b): Year = 2003

2003 means t = 13 i.e. 2003 - 1990

So:

y = (269573)/(1+985e^(-0.308*13))

y = (269573)/(1+985e^(-4.004))

y = (269573)/(1+985*0.01824)

y = (269573)/(18.9664)

y = 14213 --- approximated

Solving (c): Year = 2006

2006 means t = 16 i.e. 2006 - 1990

So:

y = (269573)/(1+985e^(-0.308*16))

y = (269573)/(1+985e^(-4.928))

y = (269573)/(1+985*0.00724)

y = (269573)/(8.1314)

y = 33152 --- approximated