The function f(x) = x is translated such that the function describing the translated graph is g(x) = (x + 5)' + 2. Whereis the point (0, 0) for the function f now located on the function g?

Answers

Answer 1
Answer:

Answer:

  (-5, 2)

Step-by-step explanation:

  g(x) = f(x -h) +k

is a translation of f(x) h units to the right and k units upward. Here, we seem to have h=-5 and k=2. That means the point (0, 0) has been translated 5 units to the left (to -5) and 2 units upward (to 2).

The translated location of (0, 0) is (-5, 2).

_____

We assume we're to ignore the apostrophe (') in the equation for g(x).


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During a nine-hour snowstorm, it snows at a rate of 2 inches per hour for the first 3 hours, at a rate of 3 inches per hour for the next 5 hours, and at a rate of 0.75 inch per hour for the final hour.How many inches of snow accumulated from the storm?

Answers

Answer:

use f(x)=y=mx+b

let snow = S, time = t instead of y and x

S(t)=mt+b

The rate of inches per hour represents the slope of the graph, m.

The y-variable would be the amount of snow, S.

The x-variable would be the time, t, in hours.

The function has three pieces:

i) S(t)= 2t (slope = 2)

ii) S(t) = 3t (slope = 3)

iii) S(t) = 0.75t (slope = 0.75)

For the first piece, i), t=3, so the amount of snow is 6 inches.

For the second piece, ii) t=5, so the amount of snow is 15 inches.

For the third piece, iii) t=1, so the amount of snow is 0.75 inch.

In total, it snowed 21.75 inches.

total snow

Final answer:

To find the total accumulation of snow during the nine-hour snowstorm, we calculate the snow accumulation for each hour and then sum them up. The total accumulation of snow from the storm is 21.75 inches.

Explanation:

To find the total accumulation of snow during the nine-hour snowstorm, we need to calculate the amount of snow that fell during each hour and then sum them up. First, we calculate the snow accumulation for each hour:

  1. For the first 3 hours, it snowed at a rate of 2 inches per hour, so the accumulation is 3 * 2 = 6 inches.
  2. For the next 5 hours, it snowed at a rate of 3 inches per hour, so the accumulation is 5 * 3 = 15 inches.
  3. For the final hour, it snowed at a rate of 0.75 inch per hour, so the accumulation is 1 * 0.75 = 0.75 inches.

Finally, we sum up the accumulations for each hour: 6 + 15 + 0.75 = 21.75 inches. Therefore, the total accumulation of snow from the storm is 21.75 inches.

Learn more about Snow accumulation here:

brainly.com/question/33175695

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A student is trying to solve the set of two equations given below:Equation A: x + z = 6
Equation B: 3x + 2z = 1

Which of the following is a possible step used in eliminating the z-term?
Multiply equation A by −2.
Multiply equation B by 2.
Multiply equation A by 3.
Multiply equation B by 3.

Answers

a possible step used in eliminating the z-term is "multiply equation A by −2."

x + z = 6
3x + 2z = 1

x + z = 6 / *(-2)
3x + 2z = 1


-2x - 2z = -12
3x+ 2z = 1

-2x + 3x -2z +2z = -12 +1
x = -11

-11 + z = 6
z = 6 + 11
z = 17

Answer:Multiply equation A by -2 is correct everyone

Step-by-step explanation:

I just took the test and checked;)

both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. how high would this water rise if it were poured into the empty wide cylinder

Answers

The height of the water when poured into the empty wide cylinder is;

Option A; To the 7¹/₃ mark

Formula for volume of a cylinder is;

V = πr²h

where;

r is radius

h is height

We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;

V_wide = 4πR²

Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;

V_narrow = 6πr²

Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;

V_wide = V_narrow

4πR² = 6πr²

⇒ R²/r² = 6/4

simplifies to get; R²/r² = ³/₂

Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;

πR²H = 11πr²

R²/r² = 11/H

Earlier, we saw that R²/r² = ³/₂. Thus;

11/H = ³/₂

H = 22/3

H =  7¹/₃

The complete question is;

Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

A) To the 7¹/₃ mark

B)To the 8th mark

C) To the 7¹/₂mark

D)To the 9th mark

E) To the 11th mark  

Read more at; brainly.com/question/16760517

Answer:

COMPLETE QUESTION:

To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark

e)To the 11th mark

ANSWER : Option D (To the 7 1/3 mark)

Step-by-step explanation:

First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e

Volume of cylinders

π x R² x 4 = πxr²x 6

R²/r² = 6/4

after both cylinder were emptied

π x R² x h = π x r² x 11

R²/r² = 6/4 = 11/h

h = (4 x 11) /6 = 22/3 = 7 1/3 mark

Therefore, the height of the water in the wide cylinder is 7 1/3

2. Use the binomial theorem to expand the expression. (а — 2b)^5

Answers

Answer:

(a-2b)^(5)=-32b^(5)+80ab^(4)-80a^(2)b^(3)+40a^(3)b^(2)-10a^(4)b+a^(5)

Step-by-step explanation:

The binomial expansion is given by:

(x+y)^(n)=_(0)^(n)\textrm{C}x^{^(0)}y^(n)+_(1)^(n-1)\textrm{C}x^(1)y^(n-1)+...+_(n)^(n)\textrm{C}x^(n)y^(0)

In our case we have

x=a\ny=-2b\nn=5

Thus using the given terms in the binomial expansion we get

(a-2b)^(5)=_(0)^(5)\textrm{C}a^(0)(-2b)^(5)+_(1)^(5)\textrm{C}a^{^(1)}(-2b)^(4)+{_(2)^(5)\textrm{C}}a^(2)(-2b)^(3)+_(3)^(5)\textrm{C}a^(3)(-2b)^(2)+_(4)^(5)\textrm{C}a^(4)(-2b)^(1)+_(5)^(5)\textrm{C}a^(5)(-2b)^(0)

Upon solving we get

(a-2b)^(5)=-32b^(5)+5* a*16b^(4)+10* a^(2) * (-8b^(3))+10* a^(3)* 4b^(2)+5* a^(4)* (-2b)+a^(5)\n\n(a-2b)^(5)=-32b^(5)+80ab^(4)-80a^(2)b^(3)+40a^(3)b^(2)-10a^(4)b+a^(5)

8/4s is proportional to what value

Answers

Step-by-step explanation:

(8)/(4)  = 2 \n

The answer is 2.

Explanation 8 divided by 4 Is 2

What is the correct relationship between events A and B: A: Laura participated in an out-of-town volleyball game at 11:00 AM last Friday. B: Laura met with her academic advisor on campus at 11:00 AM last Friday. A and B are mutually exclusive. A and B are complementary. A and B are not mutually exclusive. If B is true, A is trus

Answers

A and B are mutually exclusive