Acceleration is rate of change of velocity.
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
Determine all unknowns.
The displacement covered by the bee that flies 2 meters east, 3 meters east, and 5 meters north is 7.05 meters.
Displacement of an object can be defined as the actual change in the position of an object. It is a vector quantity because it has both the direction and the magnitude.
The bee travels 2 meter east and 3 meters east. Therefore, the total distance covered in the east direction is (2+3) meters = 5 meters.
The bee travels 5 meters in the north direction. This makes a square of 5 meters dimension and in this condition, the displacement covered by the bee will be the diagonal of the square. Therefore, the total displacement of the bee can be calculated as:
Diagonal of square = a
where, a = side of the square
Side of the square = 5 meters
Diagonal of the square = × 5
= 1.41
Therefore, diagonal = 1.41 × 5
Displacement of the bee = 7.05 meters
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(ii) it reached a uniform velocity after a short time
Answer:
1
Explanation: