11. Number Sense Jamal saysthat the sum

of 183 + 198 is less than 300. Is

Jamal's

answer reasonable? Why or

why not

Both addends are

des to 200.

Answers

Answer 1
Answer:

Answer:

Jamal's answer isn't reasonable because the sum of 183 and 198 is 381, which is way more than 300 and nowhere less than 300.

Step-by-step explanation:

Jamal makes an assertion that the sum of 183 and 198 is less than 300.

We are to check if Jamal's answer is reasonable or not.

183 + 198 = 381 > 300

The sum of the two numbers, 381, is evidently not less than 300, hence, Jamal's answer isn't reasonable because it is downright wrong.

Hope this Helps!!!


Related Questions

Please I really need help can you help me
B) How many prime numbers are multiplesof 8?
Write 8×8×8×8×8 as power ​
In a systematic review with a meta-analysis, researchers combine the results of each of the individual studies to create a larger sample size (and therefore greater power), then re-run the statistics to capture the true magnitude of the effect. The single-effect measure calculated and reported when the results from all the studies are combined is called what?
I’m not sure if my answer is correct. If you can help me

What is the answer to the problem?

Answers

Answer:

a

Step-by-step explanation:

good luck :)

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.A(n) = 1 + (n – 1)(–5.7)


1, –21.8, –56


–5.7, –21.8, –51.3


1, –16.1, –50.3


0, –17.1, –51.3


If someone answers this, i'd like if someone could help me to know how to solve it too, please and thank you!

Answers

1, - 16.1, - 50.3 ← third on list

To find the required terms, substitute n = 1, 4, 10 into the rule and evaluate

A(1) = 1 + (1 - 1)(- 5.7) = 1 + 0 = 1

A(4) = 1 + (4 - 1)(- 5.7 ) = 1 + (3 × - 5.7 ) = 1 - 17.1 = - 16.1

A(10) = 1 + (10 - 1 )(- 5.7) = 1 + (9 × - 5.7) = 1 - 51.3 = - 50.3


\bf \stackrel{A(n)=1+(n-1)(-5.7)}{ \begin{array}{ll} n\qquad \qquad &A(n)\n \cline{1-2} 1&1+(1-1)(-5.7)\n &1+0\n &1\n\n 4&1+(4-1)(-5.7)\n &1+(3)(-5.7)\n &1-17.1\n &-16.1\n\n 10&1+(10-1)(-5.7)\n &1+(9)(-5.7)\n &1-51.3\n &-50.3 \end{array} }

80 orders in 10 days = 8 orders in days

Answers

Answer:

8 orders in 1 day

Step-by-step explanation:

80 divided by 8 is 10. 8 divided by 8 is 1.

. A coin is tossed three times, and the sequence of heads and tails is recorded.(a) Determine the sample space, Ω.(b) List the elements that make up the following events: i.A= exactly two tails, ii.B= at least twotails, iii.C= the last two tosses are heads(c) List the elements of the following events: i.A, ii.A∪B, iii.A∩B, iv.A∩C

Answers

Answer:

See explanation below

Step-by-step explanation:

Here a coin was tossed three times.

Let H = head &  T = tail

Find the following:

a) The sample space:

Since a coin is tossed thrice, all possible outcome would be:

S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}

b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.

A = {HTT, TTH, THT}

ii) B = at least two tails: Here 2 or more tails were recorded.

B = {HTT, TTT, TTH, THT}

iii) C = the last two tosses are heads:

C = { HHH, THH}

c) List the elements of the following events:

i) A. This means all outcomes in A

= {HTT, TTH, THT}

ii) A∪B. A union B, means all possible outcomes present in A or B or in both

= {HTT, TTH, THT, TTT}

iii) A∩B. This means all possible outcomes of A that are present in B.

= {HTT, TTH, THT}

iv) A∩C. All outcomes A that are present in B

= {∅}

The sample space of tossing a coin three times consists of eight possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Events A, B, and C can be determined by listing the appropriate outcomes. The intersection and union of events A and B can also be determined.

(a) The sample space, Ω, of tossing a coin three times can be determined by listing all the possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT.

(b) i. A = {HHT, HTH, THH}

ii. B = {TTT, TTH, THT, HTT, HHT, HTH, THH}

iii. C = {HTH, TTH}

(c) i. A = {HHT, HTH, THH}

ii. A∪B = {HHT, HTH, THH, TTT, TTH, THT, HTT, HHT}

iii. A∩B = {HHT, HTH, THH}

iv. A∩C = {HHT, HTH}

Learn more about Sample-space of coin toss here:

brainly.com/question/32761869

#SPJ3

A family buys 8 tickets to a show. They also pay a $5parking fee. They spend $61 to see the show.
What is the solution to the story?

13.80
10.60
07.00
8.25

Answers

Answer:

C. $7.00

Step-by-step explanation:

8 times 7 is 56 + 5 = 61

What is the probability of a die coming up with the number 10?

Answers

Answer:

0

Step-by-step explanation:

0 is the probability of a die coming up with the number 10

because a die contains numbers from 1 to 6 so probability of numbers coming between are possible but 10 is not possible