Which inverse operation would be used to verify the following equation? 102 ÷ 3 = 34

Answers

Answer 1

Answer: An inverse operations is the reverse of the equation. For example, since it's 102 ÷ 3 = 34, to get the inverse you would take the opposite sign of "÷" and make it "×," while changing the equal sign to make the statement true. The inverse operation used to verify this is 102 = 3 × 34

Related Questions

A survey found that 12 out of 30 people preferred bacon over sausage. According to this survey, what percent of people prefer bacon over sausage?
What is defination of tangent
What is the most precise term for quadrilateral ABCD with vertices A(4, 4), B(5, 8), C(8, 8),and D(8, 5)? square rhombus kite Parallelogram
Which list shows these numbers in order from least to greatest? 37/6, -5.1717, √33, -26/5
How you solve b-9+6b=30

How to solve for y if the equation is y=5/2x + 5 if x is zeroplease show step by step how to solve

Answers

$y=(5)/(2)\cdot0+5\ny=0+5\ny=5$

Q, y=5/2x+x if x is zero

An, ( y=5/2×0+5 ) as you know if i multiply number to zero you get zero so "x" change to the zero you get
( y=0+5 )= ( y=5 ) that is your answer

A man walks (12x^2+11x+2) km for (3x+2) hours. What is his speed per hour?

Answers

Step-by-step explanation:

Hey there!

Distance = 12x^2+11x+2.

And Time = 3x+2 hours.

Now;

$speed = (distance)/(time)$

Putallvalues.

$s = \frac{12 {x}^(2) + 11x + 2}{3x + 2}$

Usemidtermfactorizationisnumeratorandsimplifythemtogetanswer.

$s = \frac{12 {x}^(2) + (8 + 3) x+2 }{3x + 2}$

$s = \frac{12 {x}^(2) + 8x + 3x + 2 }{3x + 2}$

$s = (4x(3x + 2) + 1(3x + 2))/((3x + 2))$

$s = ((4x + 1)(3x + 2))/((3x + 2))$

$s = (4x + 1)$

Therefore thespeedis(4x+1)/hr.

Hopeit helps..

find the area of a triangle with the following dimensions: a = 12 yards b=16 yards and c=24 yards round to the nearest square yard

Answers

Answer:c=35

Step-by-step explanation:

P=52 yards
p=26 yards
A=square p(p-a)(p-b)(p-c)
A=square26(26-12)(26-16)(26-24)
A=square 26x14x10x2
A=85 yards^2

If f(x) = x2 + 2x + 3, what is the average rate of change of f(x) over the interval [-4, 6]? A. 51

B. 40

C. 31

D. 20

E. 4

Answers

Calculating the value of f(x) for the given interval.

For x = - 4, f(x) = f(- 4) = (- 4)^2 + 2 (- 4) + 3 = 11

For x = 6, f(x) = f(6) = (6)^2 + 2 (6) + 3 = 51

Now using formula for the calculation of average rate of change of f(x) over the given interval of [- 4, 6];

(f(b) – f(a)) / b – a = (f(6) – f(- 4)) / 6 – (- 4) = (51 -11) / 10 = 4

So option “E” is correct.

Please Help me Check the image below!!!!!

Answers

Answer:

First question:

The graph of $y=(3-2x)/(2-3x)$ has a vertical asymptote at x = $(2)/(3)$ and a horizontal asymptote at y = $(2)/(3)$

Second question:

The graph of equation $y=(1-3x)/(2+x)$ has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the denominator is equal to zero

The horizontal asymptotes will occur if:

Both polynomials are the same degree, divide the coefficients of the highest degree terms
The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote

First question:

∵ $y=(3-2x)/(2-3x)$

- To find the vertical asymptote equate the denominator by 0

to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

∴ $(2)/(3)$ = x

∴ The graph has a vertical asymptote at x = $(2)/(3)$

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = $(2)/(3)$

∴ The graph has a horizontal asymptote at y = $(2)/(3)$

The graph of $y=(3-2x)/(2-3x)$ has a vertical asymptote at x = $(2)/(3)$ and a horizontal asymptote at y = $(2)/(3)$

Second question:

The graph has a horizontal asymptote at y = -3

means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3