answer is in fractions
Line segment JM has endpoints with coordinates 0 and 25 on a number line. Points K and L are on segment JM. K has a coordinate of 5 and point L has a coordinate of 12. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.
Answer:
On a Number Line, if only whole numbers are marked
Points J, M, K, and L are marked, having coordinates 0, 25, 5, and 12.
Two points are again marked on the number line.
Probability,that a point on J M is placed first on J L
= There are 10 natural numbers in between J L and 12 natural numbers between L M.
So, Required Probability
Now, Probability that second point is not placed on KL, it means that point is either is on J K or L M.
There are 4 natural number between 0 and 5 and 12 natural number between L and M.
Probability of marking second point on J M is
Probability of marking two points on the number line, with given condition is
If you consider ,points on the number line which are real numbers, then we can't find the required Probability that is marking two points on the line segment.
A. 4x
B. 4x3
C. 8x
D. 8x3
Answer:
y=1x+2
Step-by-step explanation:
the gradient is equal to 1 and the c in the question is 2 because the y-intercept represents c.
Gradient= (y2-y1)/(x2-x1)