All life that we know of is based on carbon. Carbon's ability to form many chemical bonds is an important characteristic that allows it to form the basis of life. Identify two other elements that can probably also form a large number of bonds and that probably have similar properties to carbon.
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One answer I think would be Oxygen
Calculate the volume of this regular solid.A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.
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Answer:
hes wrong its (653.45)
Explanation:
cause i got it wrong
By adding mass to the car, will we increase the average speed of the car?
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50 miles is the speed
What is the approximate diameter of an inflatedbasketball? (1) 2 × 10^–2 m (3) 2 × 10^0 m (2) 2 × 10^–1 m (4) 2 × 10^1 m
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The approximate diameter of an inflated basketball is 2 × 10^–2 m. The answer is number 1. The rest of the choices do not answer the question above because they are too big for the diameter of the basketball.
Could anyone help me figure out d and e? How can you find the work of the friction when the force of friction is not given?
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Wow ! This is not simple, Shoot, and I give you a lot of credit and an extra merit badge if you're generally keeping up with it.
I scratched my head for a few minutes, and I think I've got it. Here's what I think is going on:
KE₁ = KE of the box before pushing (1/2) (m) (speed²) = 10 x 2² = 40 joules
KE₂ = KE of the box after pushing 3m (1/2) (m) (speed²) = 10 x 4² = 160 joules
The box gained (160 - 40) = 120 J of kinetic energy.
Now look at the cluttered force diagram. Cat's component of force in the direction of motion is 120N. That's the part of her force that does the work on the box. How much work does she do ?
(force) x (distance) = (120N) x (3m) = 360 joules .
Only 120 J of that energy showed up as increased kinetic energy of the box. The other 240J of her hard-earned work was consumed by friction.
Work of friction = (Friction force) x (distance)
240 J = (friction force) x (3 m)
240 J / 3 m = friction 'force' = 80 N .
I think that's it.
What I did was:
-- Find the work that Cat did.
-- Find the increase in the kinetic energy of the box.
-- The difference ... the 'missing energy' ... was the work done by friction in the same distance.
Does this do anything for you ?
According to Charles's law whenever the temperature of a gas at constant pressure decreases the volume increases