B. Neither ultrasonic nor infrasonic vibrations can be heard by humans.
C. Infrasonic vibrations are used in sonar equipment as well as to detect flaws in steel castings.
D. Ultrasonic vibrations have a frequency lower than the range for normal hearing.
the answer is B, Good luck!
b. The electric field is decreasing.
c. The electric field is not changing.
Answer:
Option a) is correct
Explanation:
In the given question option a) ( i.e the electric field is increasing ) is correct.
The above option is correct because the electric field and the electromagnetic wave both are in the same phase of the EM wave. Thus, the electromagnetic wave and the electric field are directly proportional to each other.
In an electromagnetic wave, the electric and magnetic fields are linked, oscillating in phase. Therefore, when the magnetic field is increasing, the electric field is also increasing.
In an electromagnetic wave, the electric field and the magnetic field are perpendicular to each other and they oscillate in phase. This means when the magnetic field is increasing, the electric field is also increasing, and vice versa. So, the correct answer is option a. The electric field is increasing. It's important to keep this correlation in mind while studying electromagnetic waves, as these oscillations and their interplay are fundamental to how these waves propagate through space.
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Answer:
0.324 T
Explanation:
Parameters given:
Number of turns, N = 1850
Resistance, R = 30Ω
Area of each turn, A =
Charge in the circuit, q =
The induced EMF in the coil is given as:
EMF is also given in terms of current, I, and resistance, R, as:
V = IR =
=>
Charge, q, is the product of current and time. Hence:
It = q
=>
Hence, magnetic field, B, will be:
The magnitude of magnetic field, |B| will be |-0.324| = 0.324 T
B. Free electrons are concentrated in the P-type material and holes form in the N-type material.
C. The negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup.
D. Only a small current will flow through the diode in the forward-biased setup.