If it takes 50n of force to lift a 450n what is the ma of the machine

Answers

Answer 1
Answer:
If the machine is 100% efficient, then its
Mechanical Advantage is (450/50) = 9 .

If the machine is less than 100% efficient,
then the MA is more than 9 .


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What is the potential energy of a 1-kilogram ball is thrown into the air with an initial velocity of 30m/sec?

Answers

the ball thrown from height=0
potental energy(PE) =0
kinetic energy(KE) = 0.5mv^2 = 0.5(1)(30^2) = 450

at the highest point the ball does not moved, v=0
potential energy at its maximum
kinetic energy = 0

Energy is conserved then
total energy before = after
PE1 + KE1 = PE2 + KE2
0 + 450 = PE2 + 0

conservation of energy is fun fact
mass=1kg
g=10m/s^2 (assuming)
u=30m/s
height(h)=u^2/2g
=900/20=45m
P.E.=mgh
=1×10×45=450 joules

Which of the following statements is an accurate description of vibrations? A. The frequency of infrasonic vibrations is much too high to be heard by humans.
B. Neither ultrasonic nor infrasonic vibrations can be heard by humans.
C. Infrasonic vibrations are used in sonar equipment as well as to detect flaws in steel castings.
D. Ultrasonic vibrations have a frequency lower than the range for normal hearing.

Answers

The accurate description of vibrations is that, neither ultrasonic nor infrasonic vibrations can be heard by humans. The Infrasonic vibration frequency is lower than 20Hz, whereas ultrasonic vibration frequency is greater than 20,000Hz. The normal range of frequency of hearing for humans is only 20Hz-20,000Hz. 

the answer is B, Good luck!

At a given location in space, the magnetic field in an electromagnetic wave is increasing. How is the electric field changing at that same location? a. The electric field is increasing.
b. The electric field is decreasing.
c. The electric field is not changing.

Answers

Answer:

Option a) is correct

Explanation:

In the given question option a) ( i.e the electric field is increasing ) is correct.

The above option is correct because the electric field and the electromagnetic wave both are in the same phase of the EM wave. Thus, the electromagnetic wave and the electric field are directly proportional to each other.

Final answer:

In an electromagnetic wave, the electric and magnetic fields are linked, oscillating in phase. Therefore, when the magnetic field is increasing, the electric field is also increasing.

Explanation:

In an electromagnetic wave, the electric field and the magnetic field are perpendicular to each other and they oscillate in phase. This means when the magnetic field is increasing, the electric field is also increasing, and vice versa. So, the correct answer is option a. The electric field is increasing. It's important to keep this correlation in mind while studying electromagnetic waves, as these oscillations and their interplay are fundamental to how these waves propagate through space.

Learn more about Electromagnetic Wave here:

brainly.com/question/29774932

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A conducting coil of 1850 turns is connected to a galvanometer, and the total resistance of the circuit is 30 Ω. The area of each turn is 4.00 × 10-4 m2. This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be 8.0 × 10-3 C. Find the magnitude of the magnetic field.

Answers

Answer:

0.324 T

Explanation:

Parameters given:

Number of turns, N = 1850

Resistance, R = 30Ω

Area of each turn, A = 4.00 * 10^(-4) m^2

Charge in the circuit, q = 8.0 * 10^(-3) C

The induced EMF in the coil is given as:

V = (-NBA)/(t)

EMF is also given in terms of current, I, and resistance, R, as:

V = IR = (-NBA)/(t)

=> I*R*t = -NBA

Charge, q, is the product of current and time. Hence:

It = q

=> q*R = -NBA

Hence, magnetic field, B, will be:

B = (qR)/(-NA)

B = (8 * 10^(-3) * 30)/(-1850 * 4 * 10^(-4)) \n\n\nB = -0.324 T

The magnitude of magnetic field, |B| will be |-0.324| = 0.324 T

Which of the following accurately describes junction diodes? A. In a forward-biased setup, large numbers of charge carriers will be pulled across the junction and result in a large current.
B. Free electrons are concentrated in the P-type material and holes form in the N-type material.
C. The negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup.
D. Only a small current will flow through the diode in the forward-biased setup.

Answers

The correct answer for the question that is being presented above is this one: "C. The negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup." the statement that accurately describes junction diodes is that the negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup. 

Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and treat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?

Answers

known values; mass per / volume and mass of each atom 

average volume= volume per atom. 
density*mass per atom = volume per atom 

1cm^3 / 7.87 gram * 9.27 *10^-26 kg /atom* 1000 gram / kg=
=1.178 * 10^-22 cm^3 per atom 

Convert that to mass 
1 cm^3 * (1 m / 100 cm)^3 
 average volume= 1.178 *10^-29 m^3 per  atom 

distance: 

Volume of a cube is L^3 


so L = (1.178*10^-29)^(1/3) 

Half way through the cube is distance 1/2 L. 
Second cube is 1/2 L 
So distance between the center of 2 cubes = L 

=2.28 *10^-10 m