If a scale is 1:250,000 and the distance is 8.5cm on the map what's the actual distance
Answers
1m = 100cm therefore 1cm = 0.01m
2,125,000cm = 2,125,000 · 0.01 = 21,250m
1km = 1,000m therefore 1m = 0.001km
21,250m = 21,250 · 0.001km = 21.25km
Answer: 21,250m = 21,25km
Related Questions
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A triangle has sides measuring 5 inches and 8 inches. If x represents the length in inches of the third side, which inequality gives the range of possible values for x?.
Solve the algebraic expression n+8 if n = 15
The formula P = 2L + 2w represents the perimeter of a rectangle. In this formula,L is the length of the rectangle and w is the width. Solve the formula for L. Find the length when the width is 4 meters and the perimeter is 36 meters.
Answers
The required number would be -3/10.which is the correct answer would be option (B).
What is the number system?
A number system is defined as a way to represent numbers on the number line using a set of symbols and approaches. These symbols, which are known as digits, are numbered 0 through 9.
We have been given that two-thirds of a number is equal to a negative one-fifth.
Let the number would be x
According to the given question, the required solution would be as:
⇒ (2/3)x = -1/5
Divided by (2/3) both sides of the above equation,
⇒ (2/3)x/ (2/3) = (-1/5)/(2/3)
⇒ x = (-1/5)/(2/3)
Reciprocal the term in the numerator,
⇒ x = (-1/5) × (3/2)
Apply the multiplication operation, and we get
⇒ x = -3/10
Therefore, the required number would be -3/10.
Hence, the correct answer would be option (B).
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Answer: -7 1/2
Step-by-step explanation:
Answers
Answers
Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am
Answers
4-5x>-13 and 3-x<10
Answers
Answer:
balls
Step-by-step explanation:
c)face cards. D)black and face cards
Answers
a) 1/2, b) 1/4, c) 3/13, d) 7/26 (fraction of black and face cards) in a traditional Western pack of playing cards.
A traditional Western pack of playing cards consists of four suits: Hearts (colored red), Diamonds (colored red), Spades (colored black), and Clubs (colored black). Each suit has 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King.
a) To find the fraction of the playing cards that are red, we need to add up the number of red cards and divide by the total number of cards in the deck. There are two red suits, Hearts and Diamonds, and each has 13 cards. So there are 26 red cards in total. Since there are 52 cards in a deck, the fraction of red cards is 26/52 or 1/2.
b) To find the fraction of cards that are Diamonds, we simply divide the number of Diamonds (13) by the total number of cards (52). This gives us a fraction of 13/52 or 1/4.
c) To find the fraction of face cards, we need to add up the number of face cards and divide by the total number of cards in the deck. In each suit, there are three face cards: King, Queen, and Jack. So there are 12 face cards in each deck (4 suits x 3 face cards per suit). Therefore, there are 12/52 or 3/13 face cards in the deck.
d) To find the fraction of black and face cards, we need to count the number of black cards and the number of face cards that are also black. There are two black suits, Spades and Clubs, and each has 13 cards. So there are total 26 black cards. Of these 26 cards, there are 12 face cards (King, Queen, and Jack) which are not black, leaving 14 black cards which are face cards. Therefore, the fraction of black and face cards is 14/52 or 7/26.
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