Can anyone help with this?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

In order to find the length and width necessary to find area, we need to look at the chart. By exmaining, we can see that the length is two units from top-to-bottom. We can also see that the width is 4 units from left-to-right. We can now multiply 4 times 2 to get our answer of 8.

Answer 2

Answer:

Answer:

B. 8.0

Step-by-step explanation:

To figure out the area you just do length times width, and you find the two by counting the amount of squares they take up. The length is two, and the width is 4; therefore the area is 8

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PLEASE HELP GIVING BRAINLIEST I NEED THIS ANSWER TO GRADUATE

Answers

Answer:

area = 2.28

Step-by-step explanation:

area of triangle is 1/2*b*h

area = (1/2)*3.8*1.2

area = 2.28

Answer:

2.28

Step-by-step explanation:

Area of triangle =(base*height)/2

And base=1.2 cm

Height=38 mm ( change it to cm as they need the answer in square cm) which is 3.8 cm

So (1.2*3.8)/2=2.28

A scooter travels 30 feet in 2 seconds at a constant speed. Complete the double number line to show the distance the scooter travels after 1, 3, 4, and 5 seconds. What is the speed of the scooter in feet per second? [ Select ] What is the distance the scooter travels after 3 seconds? [ Select ] A skateboard travels 55 feet in 4 seconds. Is the skateboard going faster, slower, or the same speed as the scooter? [ Select ]

Answers

Answer:

1) 15 feet per second

2) distance after 3 seconds 45 feet

3) slower

Step-by-step explanation:

1) 30/2 = 15

2) 15 x 3

3) 55/4 = 13.75 < 15

Final answer:

The scooter travels 15 feet after 1 second, 45 feet after 3 seconds, 60 feet after 4 seconds, and 75 feet after 5 seconds. The speed of the scooter is 15 feet per second. The skateboard is going slower than the scooter.

Explanation:

To complete the double number line, we need to determine the distance the scooter travels after 1, 3, 4, and 5 seconds. Since the scooter travels 30 feet in 2 seconds at a constant speed, we can determine the distance for each time by finding the proportion:

After 1 second: 30 feet / 2 seconds = 15 feet

After 3 seconds: 30 feet / 2 seconds * 3 seconds = 45 feet

After 4 seconds: 30 feet / 2 seconds * 4 seconds = 60 feet

After 5 seconds: 30 feet / 2 seconds * 5 seconds = 75 feet

The speed of the scooter is the same as its constant speed, which is 30 feet / 2 seconds = 15 feet per second.

The distance the scooter travels after 3 seconds is 45 feet.

Since the scooter traveled 30 feet in 2 seconds, and the skateboard traveled 55 feet in 4 seconds, we can compare their speeds. The scooter traveled 30 feet in 2 seconds, which means its speed is 30 feet / 2 seconds = 15 feet per second. The skateboard traveled 55 feet in 4 seconds, so its speed is 55 feet / 4 seconds = 13.75 feet per second. Therefore, the skateboard is going slower than the scooter.

Learn more about Speed here:

brainly.com/question/28224010

#SPJ11

What is the circumference of 59 inches

Answers

By circumference we can safely assume that the figure is a circle. Assumingthat the given is radius, you are given the radius of a circle of 59 inches. Youare asked to find the circumference of the figure. The equation for thecircumference of a circle is C=2*pi*r.

C=2*pi*r
C = 2*3.723*59 inches
C = 370.71 inches
The circumference of a circle is 370.71 inches.

How do you answer this?

Answers

$(m^(-2))^5=m^(-2\cdot5)=m^(-10)$

$x^2+3x-10=\nx^2+5x-2x-10=\nx(x+5)-2(x+5)=\n(x-2)(x+5)$

(m*-2)*5 simplifies to m*-10.

This is because when you have a number with an exponent to an exponent, you multiply the exponents.

if 10 800 cm2 of material is available to make a box with a square base and an open top find the largest possible volume of the box.

Answers

Let

x--------> the length side of the square base of the box

y-------> the height of the box

we know that

The surface area of the box is equal to

$SA=4xy+x^(2)$

$SA=10,800\ cm^(2)$

$10,800=4xy+x^(2)$

$y=(10,800-x^(2))/(4x)$

$y=(2,700-0.25x^(2))/(x)$ --------> equation A

the volume of the box is equal to

$V=x^(2)y$ --------> equation B

Substitute the equation A in the equation B

$V=x^(2)*(2,700-0.25x^(2))/(x)$

$V=x*(2,700-0.25x^(2))$

$V=(2,700x-0.25x^(3))$

using a graphing tool

see the attached figure

For $x=60\ cm$

$Volume=108,000\ cm^(3)$

the point $(60,108,000)$ is a maximum of the function

Find the dimensions of the box

$x=60\ cm$

Find the value of y

$V=x^(2)y$

$y=V/x^(2)$

$y=108,000/60^(2)$

$y=30\ cm$

The dimensions of the box are

$60\ cm*60\ cm*30\ cm$

The largest possible volume of the box is

$108,000\ cm^(3)$

The largest possible volume of the box is $\boxed{108000{\text{ c}}{{\text{m}}^3}}.$

Further explanation:

Given:

The area of the material is $10800{\text{ c}}{{\text{m}}^2}.$

Explanation:

Consider the base length of the square box as “x”.

Consider the height of the box as “y”.

The surface area of the open box can be expressed as follows,

$\boxed{{\text{Surface Area}} = 4xy + {x^2}}$

The surface area of the box is $10800{\text{ c}}{{\text{m}}^2}.$

$\begin{aligned}4xy + {x^2}&= 10800\n4xy&= 10800 - {x^2}\ny&= \frac{{10800 - {x^2}}}{{4x}}\ny&=\frac{{2700 - 0.25{x^2}}}{x}\n\end{aligned}$

The volume of the box can be expressed as follows,

$\begin{aligned}V&= {x^2}y\n&= {x^2}* \left({\frac{{2700 - 0.25{x^2}}}{x}} \right)\n&= \left( x \right)* \left({2700 - 0.25{x^2}} \right)\n&= 2700x - 0.25{x^3}\n\end{aligned}$

Differentiate the volume with respect to “x”.

$\begin{aligned}\frac{{dV}}{{dx}}&= \frac{d}{{dx}}\left({2700x - 0.25{x^3}}\right)\n&= 2700 - 0.75{x^2}\n\end{aligned}$

Substitute 0 for $\frac{{dV}}{{dx}}$ in above equation to obtain the value of x.

$\begin{aligned}0&= 2700 - 0.75{x^2}\n0.75{x^2} &= 2700\n{x^2}&= \frac{{2700}}{{0.75}}\n{x^2}&= 3600\nx&= 60\n\end{aligned}$

The side of the base is $60{\text{ cm}}.$

The height of the box can be obtained as follows,

$\begin{aligned}y&= \frac{{2700 - 0.25{{\left( {60} \right)}^2}}}{{60}}\n&=\frac{{2700 - 900}}{{60}}\n&=\frac{{1800}}{{60}}\n&=30\n\end{aligned}$

The height of the box is $y = 30{\text{ cm}}.$

The volume of the box can be calculated as follows,

$\begin{aligned}V&={\left(60}\right)^2}*\left({30}\right)\n&=3600*30\n&=108000 \n\end{aligned}$

The largest possible volume of the boxis $\boxed{108000{\text{ c}}{{\text{m}}^3}}$ .

Learn more:

1. Learn more about inverse of the functionbrainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Application of Derivatives

Keywords: square, box, material, square base, volume of the box, largest, open from the top derivative, surface area.

Which best describes the solution set for the compound inequality below? (pick the best answer)2(x + 7) – 1 > 15 or 3(x + 2) < 2x + 7
A. no solution
B. x = 1
C. all real numbers except x = 1
D. all real numbers

Answers

2(x + 7) - 1 > 15 3(x + 2) < 2x + 7
2x + 14 - 1 > 15 3x + 6 < 2x + 7
2x + 13 > 15 3x - 2x < 7 - 6
2x > 15 - 13 x < 1
2x > 2
x > 2/2
x > 1

so, x > 1 OR x < 1.....all real numbers except 1

Answer:

C is your answer

Step-by-step explanation: