Find the value of angle WZX

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Answer 1

Answer: A picture is needed for this

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Help please it’s supposed to be turned in

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Answer:

30 i believe

Step-by-step explanation:

hope this helps. i say 30 because thats the only common multiple in those numbers :P

Write a formula that will compute the final grade for the course, using G to represent the final grade, H to represent the homework average, Q to represent the quiz average, P to represent the project grade, T to represent the test average, and F to represent the final exam grade. Note: Keep in mind how you must write the percentages that show the weighting of each category when doing computations!

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Answer:

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Step-by-step explanation:

Solution:

Suppose grade breakdown for certain college course is as follow:

Homework = 15%

Quizzes = 20%

Project = 10%

Test = 40%

Final exam= 15%

Let G represent the final grade

H represents homework average,

Q represents quizzes and P represent project, T represent test average and F represent final exam.

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Final answer:

The final grade, G, can be computed by adding together the weighted values of the homework average, quiz average, project grade, test average, and final exam grade. This can be represented by the formula G = 0.20*H + 0.20*Q + 0.25*P + 0.15*T + 0.20*F.

Explanation:

To compute the final grade for the course, you will need to multiply each category by its weighting percentage, then add the results together. This can be represented as the following formula:

G = 0.20*H + 0.20*Q + 0.25*P + 0.15*T + 0.20*F

In this formula, G is the final grade, H is the homework average, Q is the quiz average, P is the project grade, T is the test average, and F is the final exam grade. The coefficients (0.20, 0.20, 0.25, 0.15, and 0.20) represent the weighting percentages in decimal form for each respective category.

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The Arizona Department of Transportation wishes to survey state residents to determine what proportion of the population would like to increase statewide highway speed to 75 from 65 mph. At least how many residents do they need to survey if they want to be at least 99% confident that the sample proportion is within 0.07 of the true proportion?

Answers

Answer: 339

Step-by-step explanation:

Since the prior estimate of population proportion is unknown , then we take p= 0.5

Given : Margin of error : E=0.07

Critical value for 99% confidence interval : $z_(\alpha/2)=2.576$

Formula for sample size :-

$n=0.5(1-0.5)((z_(\alpha/2))/(E))^2\n\n=0.25((2.576)/(0.07))^2\n\n=338.56\approx339$

Hence, the minimum sample size required = 339

i.e. they need to survey 339 residents.

Final answer:

To be at least 99% confident that the sample proportion is within 0.07 of the true proportion, the Arizona Department of Transportation needs to survey at least 753 residents.

Explanation:

To determine the minimum number of residents needed to survey in order to be at least 99% confident that the sample proportion is within 0.07 of the true proportion, we can use the formula:

n = (Zα/2)2p(1-p) / E2

Where:

n is the required sample size
Zα/2 is the critical value for the desired confidence level (in this case, 99% confidence)
p is the estimated proportion (we assume 0.5 if no estimate is given)
E is the maximum allowable error (in this case, 0.07)

Plugging in the values:

Zα/2 = 2.576 (from the normal distribution table for a 99% confidence level)
p = 0.5 (since no estimate is given)
E = 0.07

Calculating n:

n = (2.576)2(0.5)(1-0.5) / (0.07)2 = 752.92

Rounding up to the nearest whole number, the Arizona Department of Transportation needs to survey at least 753 residents to be at least 99% confident that the sample proportion is within 0.07 of the true proportion.

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Karen earns $54.60 for working 6 hours. If the amount she earns varies directly with thenumber of hours she works, how many hours would she need to work to earn an
additional $260?

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Given:

Karen earns $54.60 for working 6 hours.

Amount she earns varies directly with the number of hours she works.

She need to work to earn an additional $260.

To find:

Number of hours she need to work to earn an additional $260.

Solution:

Let the amount of earnings be A and number of hours be t.

According to question,

$A\propto t$

$A=kt$ ...(i)

where, k is constant of proportionality.

Karen earns $54.60 for working 6 hours.

$54.60=k(6)$

Divide both sides by 6.

$(54.60)/(6)=k$

$9.1=k$

Put k=9.1 in (i).

$A=9.1t$

Substitute A=260 in the above equation.

$260=9.1t$

Divide both sides by 9.1.

$(260)/(9.1)=t$

$28.5714=t$

$t\approx 29$

Therefore, she need to work extra about 29 hours to earn an additional $260.

Determine whether or not the given procedure results in a binomial distribution. For those that are not binomial, identify at least one requirement that is not satisfied.a) Treating 863 subjects with Lipitor (Atorvastatin) and recording whether there is a "yes" response when they are each asked if they experienced a headache.
b) Treating 863 subjects with Lipitor (Atorvastatin) and asking each subject "How does your head feel?"
c) Twenty different Senators are randomly selected from the 100 Senators in the current Congress, and each was asked whether he or she is in favor of abolishing estate taxes.
d) Fifteen different Governors are randomly selected from the 50 Governors currently in office and the sex of each Governor is recorded.

Answers

Answer:

This procedure results in a binomial distribution

This procedure would not results in a binomial distribution

This procedure results in a binomial distribution

This procedure would not results in a binomial distribution

Step-by-step explanation:

A procedure must meet the following requirement in order for it to result in a binomial distribution

The procedure trials must be independent
Outcome of individual trials can be classified into two categories
Success probability must remain the same in all trials
The number of trials is fixed

Considering the first procedure we can see that it satisfies the requirement of above especially the requirement that the possible outcome of every trial is two

Considering the second procedure we see that would not results in a binomial distribution because the outcome of it trials cannot be classified into two categories

Considering the third procedure we can see that it satisfies the requirement of above especially the requirement that the trial must be independent

Considering the second procedure we see that would not results in a binomial distribution because there is no defined probability of success or failure

Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p-hat = 0.34 and n= 500. Point estimate ___________ (2 decimal places) Margin of error __________ (3 decimal places) The 99% confidence interval is ________ to _______ (3 decimal places)

Answers

Answer:

(a) The point estimate for the population proportion p is 0.34.

(b) The margin of error for the 99% confidence interval of population proportion p is 0.055.

Step-by-step explanation:

A point estimate of a parameter (population) is a distinct value used for the estimation the parameter (population). For instance, the sample mean $\bar x$ is a point estimate of the population mean μ.

Similarly, the the point estimate of the population proportion of a characteristic, p is the sample proportion $\hat p$ .

The (1 - α)% confidence interval for the population proportion p is:

$CI=\hat p\pm z_(\alpha/2)\sqrt{(\hat p(1-\hat p))/(n)}$

The margin of error for this interval is:

$MOE= z_(\alpha/2)\sqrt{(\hat p(1-\hat p))/(n)}$

The information provided is:

$\hat p=0.34\nn=500\n(1-\alpha)\%=99\%$

(a)

Compute the point estimate for the population proportion p as follows:

Point estimate of p = $\hat p$ = 0.34

Thus, the point estimate for the population proportion p is 0.34.

(b)

The critical value of z for 99% confidence level is:

$z={\alpha/2}=z_(0.01/2)=z_(0.005)=2.58$

*Use a z-table for the value.

Compute the margin of error for the 99% confidence interval of population proportion p as follows:

$MOE= z_(\alpha/2)\sqrt{(\hat p(1-\hat p))/(n)}$

$=2.58\sqrt{(0.34(1-0.34))/(500)}$

$=2.58* 0.0212\n=0.055$

Thus, the margin of error for the 99% confidence interval of population proportion p is 0.055.

(c)

Compute the 99% confidence interval of population proportion p as follows:

$CI=\hat p\pm z_(\alpha/2)\sqrt{(\hat p(1-\hat p))/(n)}$

$CI=\hat p\pm MOE$

$=0.34\pm 0.055\n=(0.285, 0.395)$

Thus, the 99% confidence interval of population proportion p is (0.285, 0.395).

Final answer:

The point estimate for p is 0.34. The margin of error, calculated using a z-score of 2.576, is 0.034. The 99% confidence interval is from 0.306 to 0.374.

Explanation:

This question is about calculating a confidence interval for a proportion using the normal distribution. The best point estimate for p is the sample proportion, p-hat, which is 0.34.

For a 99% confidence interval, we use a z-score of 2.576, which corresponds to the 99% confidence level in a standard normal distribution. The formula for the margin of error (E) is: E = Z * sqrt[(p-hat(1 - p-hat))/n]. Substituting into the formula, E = 2.576 * sqrt[(0.34(1 - 0.34))/500] = 0.034.

The 99% confidence interval for p is calculated by subtracting and adding the margin of error from the point estimate: (p-hat - E, p-hat + E). The 99% confidence interval is (0.34 - 0.034, 0.34 + 0.034) = (0.306, 0.374).

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