MATHEMATICS MIDDLE SCHOOL

Nine tokens are black on one side and white on the other. Initially, four tokens have the black side up (see the picture). In each turn you have to flip three tokens. What is the least number of turns you need to have all tokens showing the same color?

Answers

Answer 1

Answer:

Answer:

2 Movements

Step-by-step explanation:

Let us name the tokens

B-For Black Tokens

W-For White Tokens

The initial arrangement is therefore given as:

B-B-B-B-W-W-W-W-W

Since we are allowed to flip three tiles in each turn

First movement: Flip two blacks and one white, we would have:

B-B-W-W-W-W-W-W-B

Second movement: Flip the three black tokens, this would give us:

W-W-W-W-W-W-W-W-W

Therefore, the least number of movements to have all tokens showing the same color is 2.

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Answers

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Can someone please help me out

Answers

Answer:

Step-by-step explanation:

Answer A is the closest to being correct. I would state that the graph is vertically compressed, because that (1/4)^2 comes out to 1/16.

The other 3 answer choices are all wrong.

How is the product of 4 and 2 shown using integer tiles?A. ++++ ++
B. ---- --
C. ++ ++ ++ ++
D. -- -- -- --

Answers

Answer:

C. ++ ++ ++ ++

Step-by-step explanation:

Note that the numbers are positive 4 & positive 2 (which explains the + signs).

The answer can be two ways. 4 groups of 2, or 2 groups of 4.

C. ++ ++ ++ ++ is your answer, for it is 4 groups of 2. Note that A is not the answer, for that would be for adding, in which you have one group of 4 and one group of 2.

Answer:

Step-by-step explanation:

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