Explain why a trapezoid is a quadrilateral but a quadrilateral is not always a trapezoid.
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A trapezoid is a quadrilateral because it has 4 sides. A quadrilateral is not always a trapezoid because a quadrilateral can be any shape as long as it has four sides.
I may not make sense but I hoped this helped! :)
A quadrilateral can be any shape with 4 sides, for example parallelograms, rhombi, squares, kites, and also trapezoids. Since a quadrilateral can be any of these that I just listed, a quadrilateral is not always a trapezoid.
What is the answer to dis equationn 6+9+6+9+6+9=???
the formula F = 1.8C + 32 gives the temperature in degrees Fahrenheit (F) for a given temperature in degrees Celsius (C). There is one temperature for which the number of degrees Fahrenheit is equal to the number of degrees Celsius. Write an equation you can solve to find that temperature and then use it to find the temperature.
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f = 1.8c + 32 = c 1.8c - c = -32 0.8c = -32 c = - 40
The answer is -40 but I don't remember how to calculate that, sorry.
I need help with thisA DVD movie sells for $29 and the sales tax is 5.5%. What is the total cost of the movie to the nearest penny? Show your work to earn credit.
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29×5.5=159.5 slide the decimal 2 places to the left, so you get 1.595. That rounds up to $1.60. So $29.00+$1.60=$30.60
first you turn the tax percent into a decimal, then multiply by 29 dollars. the answer you get from multiplying you will add that to 29 $
What is the length of the actual wing of 2cm = 192 cm
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For every 1cm, there is 96cm. So multiply the number they give you by 96cm
Please helpUse p(x)=x^2+4x+9. Find a polynomial r(x) such that p(x)+r(x)=2x^2-6x+14.
Find a polynomial s(x) such that p(x)+s(x)=2x^2+14
Find a polynomial t(x) such that p(x) + t(x) has degree 2 and p(x) * t(x) has degree 3.
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Okay if you really want it simple, the answer for part C is many solutions for both such that a has a degree of 3 for p(x)•t(x) and a also has a degree of 2 for p(x)+t(x). And it a does not equal zero. I listed two examples on there. Please take a look and let me know if you have questions