MATHEMATICS HIGH SCHOOL

72. What is the prime factorization of 714?F. 2 • 357
G. 2 • 3 • 119
H. 2 • 7 • 51
J. 6 • 7 • 17
K. 2 • 3 • 7 • 17

Answers

Answer 1
Answer: Hello,
2*3*7*17=714
Answer K

Related Questions

Given the function f(x) = 2(x 8), find x if f(x) = 12. 1). 2 2). 40 3). −2 4). 14
Does anyone know the answer
Calculate cos theta to two decimal places
Which equations have the same pair of solutions? Select all that apply. n(n + 3)(n - 4) = 0 2n(4n + 6)(6n - 4) = 0 0 = 2n(6 - 4n)(4 - 6n) 0 = n(2n + 3)(3n - 2) 2n(2n + 3)(3n - 2) = 0 3n(6n + 9)(9n - 6) = 0
A = {0, 1, 2, 3}B = {a, b, c, d}C = {0, a, 2, b}Find B n C.

Solve for x.

- 36 + 7x = 76 - x

x = [?]​

Answers

Answer:

Hey there!

-36+7x=76-x

-36+8x=76

112=8x

x=14

Let me know if this helps :)

Points B and C lie on a circle with center O and radius r = 5 units. If the length of BC is 10.91 units, what is m∠BOC in radians? Use the value π = 3.1416, and round your answer to three decimal places.

Answers


Seems to me that the situation described is impossible.

If the circle's radius is 5, then its diameter is 10. The diameter of the circle
is the farthest apart that two points on the circle can be.  So points 'B' and 'C'
can not be 10.91 apart.

==========================

Oh !  But wait.  I gues you mean the distance between them along the circle.
(You just said "the length of BC", which usually means the straight-line distance.)

OK. 
The piece of the circumference that's 10.91 long is (10.91/5) radiuses long.
So the central angle that encloses it is (10.91/5) = 2.182 radians.

Answer:

m∠BOC=2.182 radians

Step-by-step explanation:

It is given that Points B and C lie on a circle with center O and radius r = 5 units, length of BC=10.91 units, then using the formula,

S=r{\theta} where S is the arc length, r is the radius and {\theta} is in radians, thus

on substituting the values of S, r, we get

⇒10.91=(5){\theta}

⇒{\theta}=(10.91)/(5)

⇒{\theta}=2.182 radians

Thus, m∠BOC=2.182 radians

What is the solution of the system of equations below?2x + 3y = 7
x + y = 3
(1) (1,2)
(2) (2,1)
(3) (4,-1)
(4) (4,1)

Answers

\begin{cases}2x + 3y = 7 \n x + y = 3 \ \ / *(-2) \end{cases}\n \n\begin{cases}2x + 3y = 7 \n -2x - 2y = -6\end{cases}\n+ \ ------- \ny=1\n \n2x + 3\cdot1 = 7

2x+3=7 \ \ |-3\n \n 2x+3-3=7-3\n \n2x=4 \ \ /:2 \n \nx=2 \n \n \begin{cases} x=2 \n y=1 \end{cases}
2x + 3y = 7
x + y = 3

x = 3 - y

substituting for x,

2(3 - y)  + 3y = 7

= 6 - 2y + 3y = 7
6 + y = 7

thus, y = 1

x = 3 - y

= 3 - 1
= 2.

Thus, x = 2 , y = 1

Thus, (2) is correct.

In a change jar, Tom has nickels and dimes. The number of nickels is two times the number of dimes and the total amount of money in the jar is $1.20. How many dimes are in the jar?

Answers

6 Dimes because if you have 6 dimes that is .60 cents then add 12 nickels that is another .60 cents so then its $1.20 :)

Answer:

40 dimes

Step-by-step explanation:

How do you spell 81 and 54?

Answers

Answer:

81- eighty one

54- fifty four

In a city school of 900 students, 35% of the students are on the honor roll, 63% have a part-time job, and 26% are on the honor roll and have a part-time job. What is the probability (rounded to the nearest whole percent) that a randomly selected student is on the honor roll, given that the student has a part-time job?41%
56%
16%
22%

Answers

Given:
900 students
35% are on the honor roll
63% have part-time jobs
26% are on the honor roll and have part-time jobs

What is the probability (rounded to the nearest whole percent) that a randomly selected student is on the honor roll, given that the student has a part-time job?

honor roll: 35% 
part time job: 63%

35% x 63% = 22.05% or 22%
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