What is the molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate, Na2SO4?0.007 mol/L
0.07 mol/L
0.0007 mol/L
0.7 mol/l
Answers
Answer:
The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7
Explanation:
Molarity is a concentration measure that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.
So, the Molarity of a solution is determined by the expression:
Molarity is expressed in units ().
In this case:
- number of moles= 0.0350
- Volume=50 mL=0.05 L (1 L= 1,000 mL)
Replacing:
Molarity= 0.7
The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7
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The subscript 2 on the Bromine, Br atom simply means Magnesium ion is; Mg²+.
Discussion:
When magnesium ion, Mg²+ combines with an halogen like Bromine, Br-.
In such scenario, there must be a balance of charges for the formation of a compound like MgBr2.
As such, 2 Br- ions and 1 Mg²+ are necessary to maintain charge balance in the compound.
Read more:
Final answer:
The '2' in Magnesium bromide (MgBr2) represents the 2 bromide ions that associate with each magnesium ion in the ionic compound, ensuring overall neutrality.
Explanation:
In the ionic compound Magnesium bromide (MgBr2), the '2' signifies the number of bromine (Br) atoms that are combined with a single atom of Magnesium (Mg) to form this compound. This is due to the fact that magnesium (Mg) has two valence electrons which it donates to form a stable compound, resulting in a Mg2+ cation. The bromine atom accepts one electron to form a Br- anion. Since Mg needs to donate two electrons, two Br ions are required, which gives us the '2' in MgBr2. This ratio of ions ensures neutrality of the overall ionic compound.
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humus is the organic component of soil formed by the decomposition of leaves and other plant material by soil microorganisms
Answer:
B. Decreased humus
Explanation:
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