Ordered pair of -x+3y=9

Answer:

5x^2+5x-1

Step-by-step explanation:

-2x^2+9x-3+7x^2-4x+2=5x^2+5x-1

The table of values for points x= 1 to x = 4 relating to the linear expression2x - 4y = 12 is given below :

• x ______ y
• 1 ______-2.5
• 2 ______-2
• 3 ______ -1.5
• 4 ______ - 1

Giventhe equation :

• 2x - 4y = 12

We could express the equation in slope - intercept form thus :

-4y = 12 - 2x

Divide both sides by - 4

y = - 3 + 0.5x

• y = 0.5x - 3

Creating the pair of points :

At ; x = 1

y = 0.5(1) - 3

y = 0.5 - 3 = -2.5

(1, - 2.5)

At point x = 2 ;

y = 0.5(2) - 3

y = 1 - 3 = - 2

(2, - 2)

At point x = 3 ;

y = 0.5(3) - 3

y = 1.5 - 3 = -1.5

(3, -1.5)

At point x = 4 ;

y = 0.5(4) - 3

y = 2 - 3 = -1

(4, - 1)

The graph of the equation is attached below.

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Answer:

Check the explanation

Step-by-step explanation:

Going by the question, the design is RBD (Randomized Block Design). Where the blocks are nothing but a Combination of Soil Types(I, II, III, IV and V).So here we have seen 5 blocks.Fertilizers can be considered as treatments(A,B and C).

Fertilizer A Fertilizer B Fertilizer C

Soil I    2                  2                 2

Soil II 2                 2                 2

Soil III 2                 2                 2

Soil III 2                 2                 2

Soil IV 2                 2                 2

Model for a randomized block design

The model for a randomized block design with one nuisance variable is

where

is any observation

μ is the general location parameter (i.e., the mean)

is the effect for being in treatment i (Fertilizer)

is the effect for being in block j (Type of Soil)

Answer:

d) The additional training did not significantly lower the defect rate

Step-by-step explanation:

Let proportion of defective chips be = x

Null Hypothesis [H0] : Additional training has no impact on defect rate             x = 8% = 0.08

Alternate Hypothesis [H1] : Additional training has impact on defect rate          x < 8% , x < 0.08  

Observed x proportion (mean) : x' = 27 / 450 = 0.06

z statistic = [ x' - x ]  / √ [ { x ( 1-x ) } / n ]

( 0.06 - 0.08 ) /  √ [ 0.08 (0.92) / 450 ]

= -0.02 / √ 0.0001635  

= -0.02  / 0.01278

z = - 1.56

Since calculated value of z, 1.56 < tabulated value of z at assumed 0.01 significance level, 2.33

Null Hypothesis is accepted, 'training didn't have defect rate reduction impact' is concluded

Answer: C

Step-by-step explanation:

When looking at compound inequalities, the inequalities are very important. You can see that on the graphs, there are some points that have a white open circle and others have blue, closed circle. The 2 different circles tells you the inequality itself. If you see ≤ or ≥, it is a closed circle. This is a closed circle because it is less than/greater than or equal to. That means it is also equal to the point, therefore it is a closed circle. If you see < or >, it is an open circle. That means it is not closed because it is greater than. It is not equal to on that specific point.

Now that we have covered the basics, we can start to eliminate. our first condition is n<-2. Above, we have established that < is an open circle. We can eliminate A and B because the points on -2 are both closed circles.

That leaves us with C and D. Since C and D both follow the points, let's look carefully at what the inequality tells us. n<-2 means n is less than -2. This means the arros should be pointing in the left side. As you go more towards the negative, the smaller the number becomes.

We can eliminate D because at -2, the numbers are going towards the right, not the left.

Therefore, our answer is C.