If the cross section shown is congruent to the base of the rectangular prism above, what is true about the crosssection?
If the cross section shown is congruent to the base - 1

Answers

Answer 1
Answer:

Answer:The answer is A.It is parallel to the basses.

Step-by-step explanation:

Answer 2
Answer:

Answer:

A its right

Step-by-step explanation:

got it right on edge


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AEFGH is a rhombus. Given EG = 22 and FH = 20, what is the length of one side of the rhombus?
Please help :/

Answers

Applying the properties of a rhombus and the Pythagorean Theorem, the length of one side of the rhombus is: 14.9

Recall:

  • The diagonals of a rhombus bisect each other at right angles, thereby forming 4 right triangles.
  • Half of a diagonal and half of the other diagonal make up a right triangle.

Thus, given:

  • EG = 22 (diagonal)
  • FH = 20 (diagonal).

Find the length of one side using Pythagorean theorem as shown below:

HG = \sqrt{((1)/(2)EG)^2 + ((1)/(2)FH)^2 } \n\n

  • Substitute

HG = \sqrt{((1)/(2) * 22)^2 + ((1)/(2) * 20)^2 } \n\nHG = √(11^2 + 10^2) \n\n\mathbf{HG = 14.9}

Therefore, applying the properties of a rhombus and the Pythagorean Theorem, the length of one side of the rhombus is: 14.9

Learn more here:

brainly.com/question/24618146

Which of these is an example of using financial reserves for a occasional expense? a. You know that your car will need a tune-up and other routine maintenance every winter, so you save a little money every month in preparation and use the saved money to pay when winter comes around. b. You are hit with a summer heat wave and your utility bill spikes, so you use your credit card to pay the bill and pay off the balance over the next few months. c. You graduate college and need to start paying back your student loans, so you devote some of your income every month to paying down the debt. d. You are never quite sure how much money you spend on food every month, and every so often you need to pull a tiny bit from your retirement fund to pay for groceries.

Answers

The correct answer is:

A) You know that your car will need a tune-up and other routine maintenance every winter, so you save a little money every month in preparation and use the saved money to pay when winter comes around.

Explanation:

An occasional expense is one that does not happen every month. Winter maintenance would count as occasional. Saving a little money each month to make sure you have enough to perform winter maintenance is using financial reserves for occasional expenses.

You guys can help me plz idc if you explain

Answers

Y=Mx+b is the answer for 15 I think

Is this correct ? .......................

Answers

To find the midpoint of the two points (x₁ ,y₁) and (x₂, y₂) we need to use the formula:

\sf{Midpoint=((x_1 + x_2)/(2), (y_1+y_2)/(2))}

So to find the midpoint of E (a,a) and F (3a, a), let's plug it in to the formula:

\sf{Midpoint=((a + 3a)/(2), (a+a)/(2))}

Simplify the numerator:

\sf{Midpoint=((4a)/(2), (2a)/(2))}

Simplifying the fractions more:

\sf{Midpoint=(2a, a)}


So the midpoint of EF is (2a,a).

Your answer of (a,a) would be wrong.

Which equation is quadratic in form?6(x + 2)2 + 8x + 2 + 1 = 0
6x4 + 7x2 – 3 = 0
5x6 + x4 + 12 = 0
x9 + x3 – 10 = 0

Answers

Answer:

Option A is correct

Step-by-step explanation:

We have been given four equations and we need to tell which one of them is quadratic

Case1:

6(x+2)^2+8(x+2)+1

In this we will use the formula (a+b)^2=a^2+b^2+2ab

Here, a=x and b=2

The equation will become 6(x^2+2^2+4x)+8x+16+1

Hence, after simplification equation will become

6x^2+24+24x+8x+16+1

6x^2+32x+41 which is a quadratic equation because quadratic equation is the equation is the equation which has degree 2.

In this equation degree is 2 hence, quadratic

Case2:

6x^4+7x^2-3  is not quadratic since, degree in this equation is 4 not 2

Hence, biquadratic not quadratic

Case3:

5x^6+x^4+12 is not a quadratic equation since, degree in this equation is 6.

Hence, not quadratic

Case4:

x^9+x^3-10 is not quadratic since, degree in this equation is 9

Hence, not quadratic

Therefore, Option A is correct

A quadratic equation is a polynomial with an order of two. Its general form is ax² + bx + c = 0. From the choices given, the first option seems to be the quadratic equation. Simplifying the equation gives 6x² + 18x + 27 = 0. 

What is the length of AC?
A.72
B.96
C.136
D.132

Answers

Answer:

The answer is 136 .