A. 1/12
B. 9/16
C. 12/13
D. 13/12
{–7, –1.7, 6.1, 10}
{–3, 4.5, 13.6, 19}
{0, 6, 9.8, 14}
{8.5, 9.1}
Answer:
its option b ( -3,4.5,13.6,19)
Step-by-step explanation:
just did it on edge 2021 <3
The equation for the graph is B.
To identify the equation for the graph, we can look at the following features:
The graph has three zeros, at x = 1, x = 3, and x = 4. This means that the equation of the graph will have the following factors: (x - 1), (x - 3), and (x - 4).
The graph is even at x = 1 and x = 4, which means that the corresponding factors must be squared.
The graph is odd at x = 3, which means that the corresponding factor must be cubed.
Therefore, the equation of the graph must be of the form:
where a, b, and c are positive integers.
To determine the values of a, b, and c, we can look at the end behavior of the graph. As x approaches positive or negative infinity, the graph goes to infinity, which means that the leading term of the polynomial must have a degree greater than 1. The leading term of the polynomial is , so we know that a + b + c > 1.
The only answer choice that satisfies all of these conditions is B.
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An expression equivalent to 3/4(5z+16) is 15/4z + 12.
Given is an expression 3/4(5z+16), we need to find the equivalentexpression,
An equivalent expression to 3/4(5z+16) can be obtained by distributing the fraction 3/4 to both terms inside the parentheses.
Here's the expression:
(3/4) x (5z + 16)
To simplify further, you can multiply the fraction 3/4 by each term inside the parentheses:
(3/4) x 5z + (3/4) x 16
This simplifies to:
15/4z + 12
Therefore, an expression equivalent to 3/4(5z+16) is 15/4z + 12.
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Answer:
The nurse should use 200cc of the 10% saline solution in order to produce a 20% saline solution.
Step-by-step explanation:
to the given mix we add a quantity of a lower mix to generate another.
50cc at 60% + Xcc at 10% = (50 + X)cc at 20%
50 x 60% + X x 10% = (50 + X) x 20%
30 + 0.1X = 10 + 0.2X
30 - 10 = 0.2X - 0.1X
20 = 0.1X
20/0.1 = X
X = 200
To produce a 20% saline solution, the nurse should use 200 cc of the 10% saline solution.
To find out how much of the 10% saline solution the nurse should use, we can set up an equation using the idea that the amount of saline in the mixture is equal to the sum of the amounts of saline in each solution.
Let's say the nurse uses x cc of the 10% saline solution. The amount of saline in the 60% saline solution will be 0.6 * 50 cc = 30 cc. The amount of saline in the 10% saline solution will be 0.1 * x cc = 0.1x cc.
Since the resulting solution is 20% saline, the total amount of saline in the mixture will be 0.2 * (50 + x) cc. Setting up the equation, we have 30 + 0.1x = 0.2 * (50 + x).
Simplifying the equation, we get 30 + 0.1x = 10 + 0.2x. Solving for x, we find that x = 200 cc.
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