consider a population of voters. suppose that that there are n=1000 voters in the population, 30% of whom favor jones. identify the event favors jones as a success s. it is evident that the probability of s on trial 1 is 0.30. consider the event b that s occurs on the second trial. then b can occur two ways: the first two trials are both successes or the first trial is a failure and the second is a success. show that p(b) = 0.3

Answer:

<8 and <6 are congruent to each other.

Step-by-step explanation:

A protractor was used to determine the answer.  They both measured to 140 degrees.  

Final answer:

Congruent angles are those that have the exact same degree measure – they are equal in size. The position of these angles does not impact their congruence.

Explanation:

In mathematics, two angles are described as congruent when they have the same measure, meaning that they are equal in degrees. For instance, if you have two angles each measuring 45 degrees, they are congruent. Even if these angles aren't located in the same position on a shape, or even on two different shapes entirely, they are considered congruent because they have the exact same degree measurement.

Congruency can also apply to other geometric elements like triangles and lines. However, in the context of your question, the concept is strictly applied to angles.

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Answer:

54 minutes

Step-by-step explanation:

Hope I helped!

I can almost guarantee this answer is correct.

Have a nice day!

Answer:

54 minutes

Step-by-step explanation:

Every 3 minutes she reads 1

18x3=54

Hope it helps

Answer: a. 0.05

b. 0.40

c. 0.85

Step-by-step explanation:

Let F= Event that a certain motorist must stop at the first signal.

S =  Event that a certain motorist must stop at the second signal.

As per given,

P(F) = 0.45 , P(S) = 0.5 and P(F or S) = 0.9

a. Using general probability formula:

P(F and S) =P(F) + P(S)-  P(F or S)

= 0.45+0.5-0.9

= 0.05

∴ the probability that he must stop at both signals = 0.05

b. Required probability = P(F but (not s)) = P(F) - P(F and S)

= 0.45-0.05= 0.40

∴ the probability that he must stop at the first signal but not at the second one =0.40

c. Required probability = P(exactly one)= P(F or S) - P(F and S)

= 0.9-0.05

= 0.85

∴   the probability that he must stop at exactly one signal = 0.85

Final answer:

The probability of stopping at both signals is 0.225, the probability of stopping at the first one but not the second one is 0.225. The probability of stopping at exactly one signal is 0.675.

Explanation:

The probability theory can be used to answer these questions. The probabilities of stopping at various traffic signals can be calculated using some assumptions about the independence of the events.

1. The probability of the motorist having to stop at both signals can be found by multiplying the individual probabilities, assuming that these are independent events. So, P(stop at both signals) = P(stop at first signal) * P(stop at second signal) = 0.45 * 0.5 = 0.225.
2. The probability of him stopping at the first signal but not at the second one is again found by multiplying the probability of stopping at the first by the probability of not having to stop at the second. Therefore, P(stop at first, not at second) = 0.45 * (1 - 0.5) = 0.225.
3. To find the probability that the driver must stop at exactly one signal, we can subtract the probability of stopping at both signals from the probability of stopping at least one signal. So, P(stop at one signal) = P(stop at at least one signal) - P(stop at both signals) = 0.9 - 0.225 = 0.675.

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Answer:

2/7

Step-by-step explanation:

-1 1/7 + 6/7 = -8/7 + 6/7 = 2/7

Answer:

No, the friend is not correct.

Step-by-step explanation:

The friend is not correct because let's call the three lines line A, line B, and line C. The line intersection says that if two lines intersect, then there will be one point of intersection. Therefore, we have to count all pairs of lines between line A, B, and C. Lines A and B can intersect, lines B and C can intersect, and lines A and C can intersect. Therefore there will be 3 lines of intersection, not 2.