Which elevation is farthest from sea level (0 feet)?220 m
-80 m
45 m
-120 m

Answers

Answer 1
Answer: That would be 220 meters.
Answer 2
Answer:

Answer:

Step-by-step explanation:

220


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PLZ HELP ME ASAP! ITS DUE TODAY!! I WILL MARK YOU BRAINLIEST IF YOU ANSWER RIGHT!! What are the new vertices for A, B and C?

You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability P(A). Write the probability as:a. a fraction in simplest form
b. a decimal
c. a percent

Answers

There are 12 letters in the mix and there are 3 letter A's. Therefore, the probability of drawing A of P(A) is:

a. a fraction in simplest form = 3/12 = 1/4
b. a decimal = 1/4 = 0.25
c. a percent = 0.25 *100% = 25%

26' long painting is how many yards long

Answers

26' long means 26 feet.

1 yard is equal to 3 feet

convert feet to yards

26 feet * 1yard/3feet = 26yard/3 = 8.67 yards or 8 2/3 yards


Monica’s school band held a car wash to raise money for a trip to a parade in New York City. After washing 125 cars, they made $775 from a combination of $5.00 quick washes and $8.00 premium washes. Let x represent the number of quick washes and let y represent the number of premium washes. Which system of linear equations represents the situation? 5x + 8y = 775 and x + y =125 5x – 8y = 125 and x + y = 775 5x + 8y = 775 and x – y = 125 5x – 8y = 125 and x – y = 775

Answers

Answer:

A. 5x + 8y = 775 and x + y =125

Step-by-step explanation:

Answer: A) 5x + 8y = 775 and x + y =125

Step-by-step explanation:

Hope this helps!

Mark me brainliest!

pls and Ty!

if r − kx, y, zl, a − ka1, a2, a3 l, and b − kb1, b2, b3l, show that the vector equation sr 2 ad sr 2 bd − 0 represents a sphere, and find its center and radius.

Answers

Answer:the center of the sphere is (1/k, 1/k, 1/k) (or (r/k, r/k, r/k) if r is taken as 1), and the radius is sqrt((1 - ka1)^2 + (1 - ka2)^2 + (1 - ka3)^2) / k.

Step-by-step explanation:

The given vector equation, s(r - kx, y, z) = s(r - ka1, a2, a3) = s(r - kb1, b2, b3) - 0, represents a sphere in three-dimensional space. To find its center and radius, we need to analyze the equation.

Let's compare the given vector equation to the standard equation of a sphere:

(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2.

From the given equation, we can identify the following:

1. Center: The center of the sphere can be found by equating the expressions inside the parentheses to zero.

Setting r - kx = 0, we find that x = r/k.

Setting r - ky = 0, we find that y = r/k.

Setting r - kz = 0, we find that z = r/k.

Therefore, the center of the sphere is (r/k, r/k, r/k), or simply (1/k, 1/k, 1/k) if r is taken as 1.

2. Radius: The radius of the sphere can be found by calculating the distance between the center and any point on the sphere.

Considering the points (r - ka1, a2, a3) and (r - kb1, b2, b3), we can calculate the distance between the center (1/k, 1/k, 1/k) and any of these points.

Using the distance formula, the distance between two points (x1, y1, z1) and (x2, y2, z2) is given by:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2).

Therefore, the radius of the sphere is d = sqrt((1/k - ka1)^2 + (1/k - a2)^2 + (1/k - a3)^2), which simplifies to sqrt((1 - ka1)^2 + (1 - ka2)^2 + (1 - ka3)^2) / k.

Prove thatsin 5x+sin3x/cos5x+cos3x=tan4x

Answers

sin5x + sin3x = 2sin4x.cosx
cos5x + cos3x = 2cos4x.cosx
so (2sin4x.cosx)/(2cos4x.cosx)(sin4x)/(cos4x)
= tan4x

Please help me!!!! So confused

Answers


Question:

The area of the kite is 48 cm². What are the lengths of the diagonals PR and QS?

________


Solution:

You can split the kite into two isosceles triangles:   PSR and PQR.

Assume that both diagonals intersect each other at the point O.


•   Area of the triangle PSR:

           m(PR) · m(OS)
A₁  =  ————————
                     2

           (x + x) · x
A₁  =  ——————
                  2


           2x · x
A₁  =  ————
              2


A₁ = x²        (i)


•   Area of the triangle PQR:

            m(PR) · m(PQ)
A₂  =  ————————
                     2

           (x + x) · 2x
A₂  =  ——————
                  2

           2x · 2x
A₂  =  ————
               2

           4x²
A₂  =  ———
             2


A₂ = 2x²        (ii)


So the total area of the kite is

A = A₁ + A₂ = 48


Then,

x² + 2x² = 48

3x² = 48

            48
x²  =  ———
            3

x² = 16

x = √16

x = 4 cm


•   Length of the diagonal PR:

m(PR) = x + x

m(PR) = 2x

m(PR) = 2 · 4

m(PR) = 8 cm


•   Length of the diagonal SQ:

m(SQ) = x + 2x

m(SQ) = 3x

m(SQ) = 3 · 4

m(SQ) = 12 cm


I hope this helps. =)


Tags:  polygon area triangle plane geometry