Answer:
6
Step-by-step explanation:
i took the quiz
Answer:
a. What is the estimated percentile for a student who scores 425 on Writing?
b. What is the approximate score for a student who is at the 87th percentile for Writing?
Answer:
a) The estimated percentile for a student who scores 425 on Writing is the 30.5th percentile.
b) The approximate score for a student who is at the 87th percentile for Writing is 613.5.
Step-by-step explanation:
Problems of normally distributed distributions are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
a. What is the estimated percentile for a student who scores 425 on Writing?
This is the pvalue of Z when X = 425. So
has a pvalue of 0.3050.
The estimated percentile for a student who scores 425 on Writing is the 30.5th percentile.
b. What is the approximate score for a student who is at the 87th percentile for Writing?
We have to find X when Z has a pvalue of 0.87. So X for Z = 1.126.
The approximate score for a student who is at the 87th percentile for Writing is 613.5.
Answer:
x = −π/2, x = π/2
Step-by-step explanation:
Given f(x) = 6x tan x and the interval −π/2 < x < π/2, we know that tan x has asymptotes in both extremes of the interval. To find the vertical asymptotes we evaluate the limit in the x-values we think asymptote can appear, in this case for x = −π/2 and x = π/2.
Then, x = −π/2 and x = π/2 are vertical asymptotes.
Answer: Does not exist.
Step-by-step explanation:
Since, given function, f(x) = 6x tan x, where −π/2 < x < π/2.
⇒ f(x) =
And, for vertical asymptote, cosx= 0
⇒ x = π/2 + nπ where n is any integer.
But, for any n x is does not exist in the interval ( -π/2, π/2)
Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.
The maximum value of f(x) is greater than the maximum value of g(x).
B.
The maximum value of g(x) is greater than the maximum value of f(x).
C.
The minimum value of f(x) is greater than the minimum value of g(x).
D.
The minimum value of g(x) is greater than the minimum value of f(x).
A. $45.00
B. $25.00
C. $4.50
D. $22.50
Ivan's annual earnings for this bond is $45.00
A bond is a pledge, made by a borrower to pay a loan taken back to the lender with an interest.
Ivan's annual interest earning would be :
= $1,000 x 4.5 %
= $45 per year
Hence, Ivan's annual earnings for this bond is $45.00
Learn more about bonds here : brainly.com/question/1392006
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What are the coordinates of point B?
Answer: the coordinates are (3,-7)
Step-by-step explanation: just took the khan academy quiz! hope you do well loves <3
To find the coordinates of point B, we first apply the midpoint formula, with point M as the midpoint and point A given. Solving for point B's coordinates we find they are (3, -7).
In order to find the coordinates of point B, we need to use the midpoint formula. The midpoint M of two points A (x1, y1) and B (x2, y2) is given as:
M = [(x1 + x2)/2 , (y1 + y2)/2].
Given that the midpoint M is (-1.5, -1) and point A is (-6,5), we can use the midpoint formula to calculate the coordinates of point B by rearranging the formula to solve for x2 and y2 (the coordinates of point B):
x2 = 2*xm - x1, y2 = 2*ym - y1.
Plugging in known values, the x-coordinate of point B (x2) = 2*-1.5 - (-6) = 3 and the y-coordinate of point B (y2) = 2*-1 - 5 = -7.
So, the coordinates of point B are (3, -7).
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Answer:
The area of the rectangle is .
Step-by-step explanation:
The perimeter of a rectangle is
where, L is length and W is width.
It is given that perimeter of a rectangle is 10m.
Divide both sides by 2.
Subtract L from both sides.
Area of a rectangle is
Substitute W=(5-L) in the above formula.
Therefore, the area of the rectangle is .