What does 4x+y=5 in finding x and y intercepts?

Answers

Answer 1

Answer:

Answer: X=5/4 Y=5

Step-by-step explanation:

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Which coordinates represent the plotted point? Check all that apply. (StartRoot 13 EndRoot, 146.3 degrees) (StartRoot 13 EndRoot, 213.7 degrees) (negative StartRoot 13 EndRoot, negative 33.7 degrees) (Negative StartRoot 13 EndRoot, negative 146.3 degrees) (−3, 2) (3, −2) (−2, 3)

Answers

Answer:

A, C, E.

Step-by-step explanation:

Just did it.

Answer:

A (square root 13, 146.3 degrees)

C (-squareroot13, -33.7 degrees)

E (-3,2)

Write a trinomial with 3x as the GCF of its terms.

Answers

Answer:

3x (x² + x + 1)

You could write any trinomial like this

4/5 divided by 1/10?

Answers

Answer:

the answer to the question is 8

8
Dividing by a fraction is the same as multiplying by its reciprocal
(4/5)/(1/10) is the same as (4/5)*(10/1)
So (4*10/5*1) =40/5=8

Find an equation for the tangent to the curve at P and the horizontal tangent to the curve at Q. y = 5 + cot x - 2 csc x 0 1 2 3 0 2 4 x y Upper QUpper P left parenthesis StartFraction pi Over 2 EndFraction comma 3 right parenthesis

Answers

Answer with explanation:

The given function in x and y is,

y= 5 +cot x-2 Cosec x

To find the equation of tangent, we will differentiate the function with respect to x

$y'= -\csc^2 x+2 \csc x* \cot x$

Slope of tangent at (π/2,3)

$y'_{((\pi)/(2),3)}= -\csc^2(\pi)/(2) +2 \csc (\pi)/(2)* \cot (\pi)/(2)\n\n=-1+2* 1 * 0\n\n= -1$

Equation of tangent passing through (π/2,3) can be obtained by

$\rightarrow (y-y_(1))/(x-x_(1))=m(\text{Slope})\n\n \rightarrow (y-3)/(x-(\pi)/(2))=-1\n\n\rightarrow 3-y=x-(\pi)/(2)\n\n\rightarrow x+y-3-(\pi)/(2)=0$

⇒There will be no Horizontal tangent from the point(π/2,3).

The pH scale measures a solution's acidity or alkalinity. The pH scale runs from 0 to 14, with 0 being the most acidic and 14 being the most alkaline. A pH of 7 is neutral (distilled water has a pH of 7). Write the pH range for the following as an inequality and label the substance as acidic or alkaline. Jerry's Fizzy Cola: 4.1 through 4.3, inclusive

A. 4.1 ≤ h ≥ 4.3, alkaline
B. 4.1 < h < 4.3, alkaline
C. 4.1 ≤ h ≤ 4.3, acidic
D. 4.1 ≤ h < 4.3, acidic

Answers

If we are to write the pH range for the Jerry's Fizzy Cola as an inequality and label the substance as acidic or alkaline, given the data 4.1 through 4.3 (inclusive), this would be the result:

C. 4.1 ≤ h ≤ 4.3, acidic

The following measurements were recorded for the drying time, in hours, of a certain brand of latex paint: 3.4, 2.5, 4.8, 2.9, 3.6, 2.8, 3.3, 5.6, 3.7, 2.8, 4.4, 4.0, 5.2, 3.0, 4.8. Assuming that the measurements represent a random sample from a normal population, find a 95% prediction interval for the drying time for the next trial of the paint.

Answers

Answer:

The 95% confidence interval for the mean is (3.249, 4.324).

We can predict with 95% confidence that the next trial of the paint will be within 3.249 and 4.324.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean.

As the population standard deviation is not known, we will use the sample standard deviation as an estimation.

The sample mean is:

$M=(1)/(15)\sum_(i=1)^(15)(3.4+2.5+4.8+2.9+3.6+2.8+3.3+5.6+3.7+2.8+4.4+4+5.2+3+4.8)\n\n\n M=(56.8)/(15)=3.787$

The sample standard deviation is:

$s=\sqrt{(1)/((n-1))\sum_(i=1)^(15)(x_i-M)^2}\n\n\ns=\sqrt{(1)/(14)\cdot [(3.4-(3.787))^2+(2.5-(3.787))^2+(4.8-(3.787))^2+...+(4.8-(3.787))^2]}\n\n\n$ $s=\sqrt{(1)/(14)\cdot [(0.15)+(1.66)+(1.03)+...+(1.03)]}$

$s=\sqrt{(13.197)/(14)}=√(0.9427)\n\n\ns=0.971$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=3.787.

The sample size is N=15.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=(s)/(√(N))=(0.971)/(√(15))=(0.971)/(3.873)=0.2507$