MATHEMATICS HIGH SCHOOL

Find cotx if sinx cotx cscx = sqrt2

Answers

Answer 1

Answer:

Answer:

$cot(x)=\sqrt2$

Step-by-step explanation:

$sin(x)cot(x)csc(x) = \sqrt2$ , csc(x) = 1/sin(x)

$sin(x)cot(x)((1)/(sin(x))) = \sqrt2$

$cot(x)=\sqrt2$

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Ava's dog weighs 56 kilograms. Marty's dog weighs 7/8 as much. How much does Marty's dog weigh?

Answers

Answer:

49 kg.

Step-by-step explanation:

We have been given that Ava's dog weighs 56 kilograms. Marty's dog weighs 7/8 as much. We are asked to find the weight of Marty's dog.

To find the weight of Marty's dog, we will multiply 56 by $(7)/(8)$ .

$\text{Weight of Marty's dog}=56\text{ kg}* (7)/(8)$

$\text{Weight of Marty's dog}=7\text{ kg}* 7$

$\text{Weight of Marty's dog}=49\text{ kg}$

Therefore, the weight of Marty's dog is 49 kilograms.

49 kilograms!
56:8=7 (is the 1\8)
so the 7\8 are 7*7=49 kilograms

Please help! If you do so you will get 50 points and brainiest!

Answers

Answer:

Step-by-step explanation:

Answer: 1

Explanation: 0v0

A line passes through (1,1) , (-2,4) , and (6,n) . Find the value of n.

Answers

Answer:

$n=-4$

Step-by-step explanation:

The line passes through the points $\left ( 1,1 \right ),\:\left ( -2, 4\right ),\:\left ( 6,n \right )$

We know that equation of a line passing through two given points $\left ( x_(1),y_(1) \right )$ and $[tex]y-1=(4-1)/(-2-1)\left ( x- 1\right )$ [/tex]

Here, $x_(1) =1, x_(2) =-2,y_(1) =1,y_(2) =4$

So, equation of the line is $y-1=(4-1)/(-2-1)\left ( x- 1\right )$

$y-1=(3)/(-3)\left ( x- 1\right )$

$y-1=-x+1$

$x+y=2$

So, the equation of the line is $x+y=2$ .

As, the point $(6,n)$ lies on the line, will satisfy the equation of the line.

$6+n=2\:\:\left [\because x=6,y=n\right ]$

$n=-4$

Hence, the value of n is $-4$ .

-4.

The equation for a line is y-y₁=m(x-x₁)
Using the following:
x₁= 1
x₂= -2
y₁= 1
y₂= 4

and slope, or m, is (x₂-x₁)/(y₂-y₁),

You can now fill out the equation!
y-(1)=-1(x-(1))
y= -x+2

And solve by substituting the 6, or x₃, into the equation to find the corresponding y value:

y= -(6)+2
y= -4

Therefore,
n=-4

A 12-foot tree casts a 22-foot shadow. Find the angle of elevation from the tip of the shadow to the top of the tree. Round the answer to the nearest tenth.

Answers

The angle of elevation from the tip of the shadow to the top of the tree is one of the acute angles of the right triangle. The 22-ft shadow is the length of the adjacent side of the angle and 12-ft tree the opposite side. The angle asked for in the problem is the arctan of 12-ft divided by 22-ft. Thus, the angle of elevation is 28.61 degrees.

Answer:

Step-by-step explanation:

I just did it

An equilateral triangle has a side length of 10 inches. Find the length of the triangle's altitude

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the altitude is 10 inches
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If BC= 6.5, CD= 7.8, and AD=12.2, find AB to the nearest tenth

Answers

Assuming that each of these letters are splitting this half and half (based off of the information given here) then AB would be 9.4

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