Use the table below to answer the following question(1,1)
(2,4)
(3,9)
(4,16)
which is not true about the above table?
A .It shows a linear function.
B .The variable x increases by 1 each time.
C .The rate of change is not constant.
D. The variable y increases by a different value each time

Answers

Answer 1
Answer: A. false
B. true
C. true
D. true

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What is 48% expressed as a fraction in simplest form?
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A) dilations always increase the length of line segmentsB) dilations take right angles to right angles

C) dilations of an angle are congruent to the original angle

D) dilations increase the measure of angles

E) dilations of a triangle are congruent to the original triangle

F) dilations dilations of a triangle are similar to the original triangle​

Answers

Answer:

it ccccccccccccccccc

hope i help you

i hatee when tell me when i do not make  not make sense yea fakeeeeeeeeeeeee

give me like an i add yea backkkkkkkkkkkkkkkkk

Step-by-step explanation:

What is the perimeter of the triangle expressed as a polynomial? Length: 8x-2
Length: 5x-4
Width: 9x-3
If you could show me how you got the complete answer I would really appreciate it.

Answers

The perimeter is the sum of the lengths of the three sides of the triangle. If "width" is the length of the 3rd side, then the perimeter is
  P = (8x-2) + (5x-4) + (9x-3)
  P = 8x + 5x + 9x -2 -4 -3
  P = (8+5+9)x -(2+4+3)
  P = 22x - 9

Which of the following is the probability of drawing a black card or a face card from a standard deck of cards?1/2
19/26
3/26
8/13

Answers

The required probability = 8/13 since option D is the correct answer.

What do we mean by probability?

The probability of any outcome is the ratio of the number of favorable outcomes to the total number of possible outcomes.

How do we calculate the probability in the given question?

A standard deck of cards contains 52 cards.

∴ Total number of possible outcomes n(S) = 52

Number of black cards in a standard deck = 26

Number of face cards in a standard deck = 12

But, black face cards have already been counted in the black cards, so we subtract the number of black face cards = 6.

∴ Number of favorable outcomes n(A) = 26 + 12 - 6 = 32

Probability (A black card or a face card) = n(A)/n(s) = 32/52 = 8/13

∴ The required probability = 8/13. The correct option is D.

Learn more about Probability at

brainly.com/question/25870256

#SPJ2

1) Well, we know there are 52 cards in a deck.
So, we would divide 52 by 2 because half of the cards are black, half red. So, that means the fraction would have to be of half of 52.  1/2 would be the correct fraction for getting a black card out.
2) There are 12 faced cards in one deck. (That is about as much as I for sure know)

Kevin is looking at two brands of washing machines. Between water and electricity, a Brand C washer uses about $0.65 per load, and a Brand D washer uses about $0.27 per load. Kevin averages about five loads of laundry per month. After one year, how much more would the utility costs for a Brand C washer be than the utility costs for a Brand D washer?a.
$22.80
b.
$16.20
c.
$7.60
d.
$19.00

Answers

Answer:

a.  $22.80

Step-by-step explanation:

Given :

Brand C washer uses about $0.65 per load

Brand D washer uses about $0.27 per load

Kevin averages about five loads of laundry per month.

To Find :how much more would the utility costs for a Brand C washer be than the utility costs for a Brand D washer after one year?

Solution :

The utility cost of Brand C washer  per load = $0.65

Since she uses 5 loads per month

So, she uses loads in 12 months(=1year) = 5*12 =60 loads

Now cost of 60 loads is 60*0.65 = $39

Thus the utility cost of Brand C for 1 year is $39

The utility cost of Brand D washer  per load = $0.27

Since she uses 5 loads per month

So, she uses loads in 12 months(=1year) = 5*12 =60 loads

Now cost of 60 loads is 60*0.27 = $16.2

Thus the utility cost of Brand D for 1 year is $16.2

The difference between their 1 year costs = $39-$16.2 = $22.8

Thus the utility costs for a Brand C washer will be $22.8 more than the utility costs for a Brand D washer.

Hence Option A is correct.





The correct answer is A. $22.80.

Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths.x2 + y2 − 2x + 2y − 1 = 0
x2 + y2 − 4x + 4y − 10 = 0
x2 + y2 − 8x − 6y − 20 = 0
4x2 + 4y2 + 16x + 24y − 40 = 0
5x2 + 5y2 − 20x + 30y + 40 = 0
2x2 + 2y2 − 28x − 32y − 8 = 0
x2 + y2 + 12x − 2y − 9 = 0

Answers

The correct answer is:

x²+y²-2x+2y-1 = 0;
x²+y²-4x+4y-10 = 0;
5x²+5y²-20x+30y+40 = 0;
x²+y²-8x-6y-20 = 0;
x²+y²+12x-2y-9 = 0;
4x²+4y²+16x+24y-40 = 0; and 
2x²+2y²-28x-32y-8 = 0

Explanation:

For each of these, we want to write the equation in the form
(x+h)²+(y+k)² = r².

To do this, we evaluate the terms 2hx and 2ky in each equation.  We will take half of this; this will tell us what h and k are for each equation.

For the first equation:
2hx = -2x and 2ky = 2y.

Half of -2x = -1x and half of 2y = 1y; this means h = -1 and k = 1:
(x-1)² + (y+1)² + ___ - 1 = 0

When we multiply (x-1)², we get
x²-2x+1.
When we multiply (y+1)², we get
y²+2y+1.

This gives us 1+1 = 2 for the constant.  We know we must add something to 2 to get -1; 2 + ___ = -1; the missing term is -3.  Add that to each side (to have r² on the right side of the equals) and we have
(x-1)² + (y+1)² = 3
This means that r² = 3, and r = √3 = 1.732.

For the second equation, 2hx = -4x and 2ky = 4y; this means h = -4/2 = -2 and k = 4/2 = 2.  This gives us
(x-2)² + (y+2)² -10 + ___ = 0.

Multiplying (x-2)² gives us
x²-4x+4.
Multiplying (y+2)² gives us
y²+4x+4.
This gives us 4+4= 8 for our constant so far.

We know 8 + ___ = -10; this means the missing term is -18.  Add this to each side of the equation to have
(x-2)²+(y+2)² = 18; r² = 18; r = √18 = 3√2 = 4.243.

For the third equation, 2hx = -8x and 2ky = -6y.  This means h = -8/2 = -4 and k = -6/2 = -3.  This gives us:
(x-4)²+(y-3)²-20 = 0

Multiplying (x-4)² gives us
x²-8x+16.
Multiplying (y-3)² gives us
y²-6y+9.

This gives us 16+9 = 25 for the constant.  We know that 25+___ = -20; the missing term is -45.  Add this to each side for r², and we have that 
r²=45; r = √45 = 3√5 = 6.708.

For the next equation, we factor 4 out of the entire equation:
4(x²+y²+4x+6y-10)=0.
This means 2hx = 4x and 2ky = 6y; this gives us h = 4/2 = 2 and k = 6/2 = 3.  This gives us
4((x+2)²+(y+3)² - 10) = 0.

Multiplying (x+2)² gives us
x²+4x+4.
Multiplying (y+3)² gives us
y²+6y+9.

This gives us a constant of 4+9 = 13.  We know 13+__ = -10; this missing value is -23.  Since we had factored out a 4, that means we have 4(-23) = -92.  Adding this to each side for r², we have
r²=92; r = √92 = 2√23 = 9.59.

For the next equation, we factor out a 5 first:
5(x²+y²-4x+6y+8) = 0.  This means that 2hx = -4x and 2ky = 6y; this gives us h = -4/2 = -2 and k = 6/2 = 3:

5((x-2)²+(y+3)²+8) = 0.

Multiplying (x-2)² gives us
x²-4x+4.
Multiplying (y+3)² gives us
y²+6y+9.

This gives us a constant of 4+9 = 13.  We know that 13+__ = 8; the missing value is -5.  Since we factored a 5 out, we have 5(-5) = -25.  Adding this to each side for r² gives us
r²=25; r = √25 = 5.

For the next equation, we first factor a 2 out:
2(x²+y²-14x-16y-4) = 0.  This means 2hx = -14x and 2ky = -16y; this gives us h = -14/2 = -7 and k = -16/2 = -8:

2((x-7)²+(y-8)²-4) = 0.

Multiplying (x-7)² gives us
x²-14x+49.
Multiplying (y-8)² gives us
y²-16x+64.

This gives us a constant of 49+64=113.  We know that 113+__ = -4; the missing value is -117.  Since we first factored out a 2, this gives us 2(-117) = -234.  Adding this to each side for r² gives us
r²=234; r = √234 = 3√26 = 15.297.

For the last equation, 2hx = 12x and 2ky = -2; this means h = 12/2 = 6 and k = -2/2 = -1:
(x+6)²+(y-1)²-9 = 0

Multiplying (x+6)² gives us
x²+12x+36.
Multiplying (y-1)² gives us
y²-2y+1.

This gives us a constant of 36+1 = 37.  We know that 37+__ = -9; the missing value is -46.  Adding this to each side for r² gives us
r² = 46; r=√46 = 6.78.
Find the radius of each equation:

1.
 x^2 + y^2-2x+2y-1 = 0, \n x^2-2x+1-1 + y^2+2y+1-1-1 = 0, \n (x-1)^2+(y+1)^2=3, then r_1= √(3).

2. 
x^2 + y^2-4x + 4y- 10 = 0, \n x^2 -4x+4-4+ y^2 + 4y+4-4- 10 = 0, \n (x-2)^2+(y+2)^2=18, then r_2= √(18)=3 √(2).

3.
 x^2 + y^2-8x- 6y- 20 = 0, \n x^2-8x+16-16+ y^2- 6y+9-9- 20 = 0, \n (x-4)^2+(y-3)^2=45, then r_3= √(45) =3 √(5).


4.
4x^2 + 4y^2+16x+24y- 40 = 0, \n 4x^2+16x+16-16+ 4y^2+24y+36-36- 40 = 0, \n 4(x+2)^2+4(y+3)^2=92,\n (x+2)^2+(y+3)^2=23, then r_4= √(23).

5.
 5x^2 + 5y^2-20x+30y+ 40 = 0, \n 5x^2-20x+20-20+ 5y^2+30y+45-45- 40 = 0, \n 5(x-2)^2+5(y+3)^2=105,\n (x-2)^2+(y+3)^2=21, then r_5= √(21).

6.
 2x^2 + 2y^2-28x-32y- 8= 0, \n 2x^2-28x+98-98+ 2y^2-32y+128-128- 8= 0, \n 2(x-7)^2+2(y-8)^2=234,\n (x+2)^2+(y+3)^2=117, then r_6= √(117)=3√(13).

7. 
x^2 + y^2+12x-2y-9 = 0, \n x^2+12x+36-36+ y^2-2y+1-1- 9 = 0, \n (x+6)^2+(y-1)^2=46, then r_7= √(46).

Hence
r_1= √(3), r_2=3 √(2), r_3=3 √(5), r_4= √(23), r_5= √(21), r_6= 3√(13), r_7= √(46) and r_1\ \textless \ r_2\ \textless \ r_5\ \textless \ r_4\ \textless \ r_3\ \textless \ r_7\ \textless \ r_6.











Which ondered pair is the solution to this system of equations? y=x+4 x+y=2 (1) (1,5) (2) (0,2) (3)(-1,3) (4)(-4,0)

Answers

Solve the following system:

{y = x + 4 | (equation 1)

y + x = 2 | (equation 2)

Express the system in standard form:

{-x + y = 4 | (equation 1)

x + y = 2 | (equation 2)

Add equation 1 to equation 2:

{-x + y = 4 | (equation 1)

0 x + 2 y = 6 | (equation 2)

Divide equation 2 by 2:

{-x + y = 4 | (equation 1)

0 x + y = 3 | (equation 2)

Subtract equation 2 from equation 1:

{-x + 0 y = 1 | (equation 1)

0 x + y = 3 | (equation 2)

Multiply equation 1 by -1:

{x + 0 y = -1 | (equation 1)

0 x + y = 3 | (equation 2)

Answer: x = -1 y = 3