In general, embolism occur: a. in the vessel elements and tracheids after turgor loss point through air-seeding across pit membranes b. in vessel elements only, after turgor loss point through air-seeding across pit membranes c. in the vessel elements and tracheids after turgor loss point through air-seeding across plasmodesmata d. in vessel elements only, after turgor loss point through air-seeding across plasmodesmata

Answers

Answer 1

Answer:

Answer:

b. in vessel elements only, after turgor loss point through air-seeding across pit membranes

Explanation:

As in humans, embolism can happen in plants. In the case of plants, embolism occurs only in the elements of the vessel, after the point of loss of the turgor through the propagation of air through the membranes of the pits, in other words, the embolism occurs when there is air filling the empty spaces of the xylem (element of vase), creating air bubbles.

These air bubbles block the xylem's work in transporting water from the root to the other parts of the plants, that is, it reduces the plant's ability to absorb water from the soil, thus preventing the plant from carrying out not only photosynthesis, but numerous metabolic processes essential for your body to survive.

Answer:

The acceleration of the object is 1.667 m/s2.

Explanation:

Given data:

Initial velocity = v1 = 6 m/s

Final velocity = v2 = 11 m/s

Time period = t = 3 s

Solution:

Acceleration = a = ( v2 - v1)/t

By putting values in the above formula:

Acceleration = a = (11 - 6)/3

a = 5/3 = 1.6667

Explanation:

Acceleration of an moving object is the change of velocity of an object divided by the total time taken by the object which is time period. So by putting values it comes that acceleration of object is 1.6667 m/s2.

The unit is meter per second square.

Which plant tissue is responsible for conducting water from the root to the stem or leaves

Answers

Answer:

Xylem Tissue

Explanation:

Xylem, plant vascular tissue that conveys water and dissolved minerals from the roots to the rest of the plant

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The table in Figure 12–3 shows the results of measuring the percentages of the four bases in the DNA of several different organisms. Some of the values are missing from the table. Based on Chargaff’s rule, the percentages of thymine bases in chicken DNA should be aroundA. 28.8%.
B. 19.9%.
C. 21.5%.
D. 13.4%.

Answers

The correct answer to this question is letter "B. 19.9%. "

There exists a question on a separate site that shows that table.
The table in Figure 12–3 shows the results of measuring the percentages of the four bases in the DNA of several different organisms. Some of the values are missing from the table. Based on Chargaff’s rule, the percentages of thymine bases in chicken DNA should be around 19.9%

When does oxyhemoglobin form during respiration? Group of answer choices during internal respiration immediately after carbon dioxide enters the blood when the chloride shift occurs during external respiration

Answers

Answer:

during external respiration

Explanation:

Oxyhemoglobin is a type of hemoglobin carrying oxygen which is bright red in color. In the blood, it's major function is to carry oxygen molecules throughout the body.

Oxyhemoglobin is formed during external respiration. External respiration also known as breathing occurs in the lung. During external respiration, there is an exchange of oxygen and carbon-dioxide between the cells of the body and blood vessels. During breathing, oxygen diffuses into the blood, the oxygen then binds with heme in the hemoglobin found in erythrocytes to form oxyhemoglobin.

Answer:

during external respiration

Explanation:

Oxyhemoglobin is a protein formed when hemoglobin is combined with an oxygen molecule during lung respiration, also called external respiration. Its function is to transport oxygen throughout the body.

External breathing is performed when we breathe in oxygen into the body. This oxygen will be used for cells to perform cellular respiration that will be responsible for exhaling carbon dioxide out of our body.

Suppose Sally grew a wild type E. coli culture in rich liquid media that contained all 20 amino acids until the culture was dividing exponentially, with one cell division approximately every 20 minutes. She then added the mutagen 5-bromouracil to the media. After the cells had grown for 20 more minutes, she washed the cells to remove the mutagen and resuspended the washed cells in sterile water. Next, Sally plated the resuspended cells on minimal media supplemented with tryptophan and obtained well-separated colonies, such that each colony arose from a single bacterial cell. She replica-plated these colonies on minimal media and selected a single colony that grew on the media supplemented with tryptophan, but not on minimal media.
Sally inoculated 10 test tubes containing fresh minimal media supplemented with tryptophan with cells from this colony and grew the 10 cultures until the cells were dividing exponentially. She then plated 0.1 mL of each culture onto separate plates containing minimal media.
No colonies grew on 3 of the 10 plates. Colonies grew on the remaining seven plates, with one plate containing about 100 colonies and the other plates each containing between 1 and 15 colonies. What type of mutation allowed colonies to grow on these seven plates?
a) spontaneous forward mutation
b) spontaneous reverse mutation
c) induced forward mutation
d) induced reverse mutation

Answers

Answer:

b) spontaneous reverse mutation

Explanation:

Spontaneous mutations are produced by natural biological processes, while induced mutations are produced by mutagenic agents that trigger nucleotide errors in the DNA sequence. In the first phase of the experiment, Sally generated an induced mutation by using 5-bromouracil. The resulting strain required a constant supply of tryptophan to grow.

A reverse mutation restores the wild-type phenotype modified by a forward mutation, thereby reversing the phenotypic alteration to its original state. In a second step of the experiment, the colonies grew without the supply of tryptophan, thereby evidencing that the mutation was reversed in the original colony.

Evaporative cooling is a product of evolution that has evolved in some organisms for use under certain environmental conditions. Circle the organisms or conditions below that you think are most likely to use evaporative cooling.

Answers

Answer:

In order to lower the temperature.

Explanation:

Mammals and birds uses evaporative cooling due to their high body temperature because this evaporative cooling removes the high temperature from the body. In this process, the water present in the body absorb all the extra heat and remove this extra heat from the body with change its state from liquid to vapors and the body's temperature cools down. This evaporative cooling is occurs in the process of sweating.

Final answer:

Evaporative cooling is an evolution-driven thermal regulation method that certain organisms utilise to cool their bodies. It mainly occurs in organisms living in hot environments like kangaroos.

Explanation:

Evaporative cooling is a biological process related to evolution and is used as a thermal regulatory method by certain organisms. Evaporative cooling occurs when an organism excretes water from its body surface, which then evaporates, absorbing heat and subsequently leading to cooling. This evolutionary adaptation generally occurs in organisms that live in warm or hot environments where they are exposed to high temperatures. An example of an organism using evaporative cooling is the kangaroo, which licks its forearms, allowing the saliva to evaporate and cool its body during intense heat.