Data on caloric intake or teens for two types of diet are given below. Typical Diet Caloric intake Sample mean St. Dev.
No fast food 2310 2295 2280 2340 2235 2265 2315 2291.429 34.8466
food Fast 2579 2160 2165 2580 2558 2591 2614 2518 2583.125 33.0646
Give a 95% confidence interval for the difference of the two means, (Uf - Un), where is the mean calorie intake for teens who typically eat fast food and is that for teens who do not typically eat fast food assuming two normal populations, independent random samples, and equal variances for the two populations
Answers
Answer:
Step-by-step explanation:
For "no fast food,
n1 = 9
Mean = (2310 + 2295 + 2280 + 2340 + 2235 + 2265 + 2315 + 2291.429 + 34.8466)/9
Mean, m1 = 2041
Standard deviation, s1 = √summation(x - u)²/n
summation(x - u)² =
(2310 - 2041)^2 + (2295 - 2041)^2 + (2280 - 2041)^2 + (2340 - 2041)^2 + (2235 - 2041)^2 + (2265 - 2041)^2 + (2315 - 2041)^2 + (2291.429 - 2041)^2 + (34.8466 - 2041)^2
= 4533653.14837256
s = √4533653.14837256/9
s = 709.75
For " fast food",
n2 = 10
Mean = (2579 + 2160 + 2165 + 2580 + 2558 + 2591 + 2614 + 2518 2583.125 + 33.0646)/10
Mean,m2 = 2238
summation(x - u)² =
(2579 - 2238)^2 + (2160 - 2238)^2 + (2165 - 2238)^2 + (2580 - 2238)^2 + (2558 - 2238)^2 + (2591 - 2238)^2 + (2614 - 2238)^2 + (2518 - 2238)^2 + (2583.125 - 2238)^2 + (33.0646 - 2238)^2
= 5672294.38379816
s2 = √5672294.38379816/10
s2 = 753.15
For a confidence interval of 95%, z = 1.96
The formula for confidence interval is
m1 - m2 ± z × √(s1²/n1 + s2²/n2)
= 2041 - 2238 ± 1.96 × √(709.75²/9 + 753.15²/10)
= - 197 ± 1.96 × √(55971.6736 + 56723.4923)
= - 197 ± 1.96 × 335.7
= - 197 ± 657.972
The lower end of the interval is
- 197 - 657.972 = - 854.972
The upper end of the interval is
- 197 + 657.972 = 460.972
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The work done by the man against gravity in climbing to the top is 16740 lb-ft
What is work done against gravity?
The work done against gravity relies on the height of the object and the weight at which the object is changing.
From the given information:
Taking the vertical y-axis when y = 0, then:
- The weight of the paint w(y) becomes;
w(0) = 20 lb
w(90) = 20 - 8 = 12 lb
Provided that the paint leaks steadily, the function of y i.e. w(y) can be expressed as a linear function in the form:
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Thus;
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Answers
Complete Question
Let x be a continuous random variable that follows a normal distribution with a mean of 550 and a standard deviation of 75.
a
Find the value of x so that the area under the normal curve to the left of x is .0250.
b
Find the value of x so that the area under the normal curve to the right ot x is .9345.
Answer:
a
b
Step-by-step explanation:
From the question we are told that
The mean is
The standard deviation is
Generally the value of x so that the area under the normal curve to the left of x is 0.0250 is mathematically represented as
Generally the critical value of 0.0250 to the left is
=>
=>
=>
Generally the value of x so that the area under the normal curve to the right of x is 0.9345 is mathematically represented as
Generally the critical value of 0.9345 to the right is
=>
=>
=>
-5x + 4y = -13
A. (0, -1)
B. (8,0)
C. (1, -7/8)
D. (2, -3/4)
Answers
Answer:
D. (2, -3/4)
Step-by-step explanation:
Using the substitution method:
-5x+4(1/8x-1)=-13
-5x+0.5x-4=-13
-4.5x/4.5=-9/4.5
-x=-2
x=2
You are supposed to replace 2 in the first equation now but as there is no other option with x value of 2 D is the answer.
If continued:
-5(2)+4y=-13
-10+4y=-13
4y=-3
y=-3/4
B) 124.96 ounces
C) 125.56 ounces
D) 125.96 ounces
Answers
9514 1404 393
Answer:
B) 124.96 ounces
Step-by-step explanation:
To find ounces, multiply the number of grams by the number of ounces in each gram.
3550 × 0.0352 = 124.96 . . . ounces
Answers
Answer:
in standered form -
3x²+4x−14=0
Step-by-step explanation:
Hope this helps :)
Answers
Answer:
G
Step-by-step explanation:
a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.