Answer:
4/3 pi radius cubed
Step-by-step explanation:
4/3 pi x (8x8x8)
512 x 4/3 pi
2144.660585
The maximum area that can be roped off with 200 feet of rope is 2500 square feet by making the roped off area a square.
The question deals with the optimization of area given a fixed perimeter, which involves the principles of geometry and algebra. Since the area needs to be roped off is a rectangle, and you have 200 feet of rope, your rectangle will have dimensions length (L) and width (W) such that 2L + 2W = 200.
To maximize the area of a rectangle given a fixed perimeter, the rectangle should be a square. So, for a maximum area, the length and width should be equal. Thus, each dimension (length and width) would be 200/4 = 50 feet.
Finally, to find the maximum area, we multiply the length by the width: 50 feet * 50 feet = 2500 square feet. So, the maximum area that they can rope off with 200 feet of rope is 2500 square feet.
#SPJ3
f(x) = 2,000(0.94)x, 952 square kilometers
f(x) = 2,000(1.06)x, 4,204 square kilometers
f(x) = 2,000(0.06)x, 1,239 square kilometers
f(x) = 2,000(0.94)x, 1,432 square kilometers
Answer:
13.26
Step-by-step explanation:
The computation of the height should be computed by using the Pythagoras theorem
As we know that
Hypothenuse^2 = base^2 + height^2
where,
Hypothenuse is 15 foot
And, the foot of the ladder i.e base is 7
So now placing these values
The height is
15^2 = 7^2 + height^2
225= 49 + height^2
After solving this, the height is 13.26
Answer: 120
Step-by-step explanation: 3/10=0.3
0.3*400=120