The product of two integers is 50. one integer is twice the other. find the integers.

Answers

Answer 1
Answer: (1) -5*(-10)=50
(2) 5*10=50
Answer 2
Answer: use what they are telling. 

a*b=50 (one integer times the other give you a product of 50. we're randomly calling these integers "a" and "b")

2a=b (one integer is twice the amount of the other. we're randomly selecting "b" to be twice the amount of "a")

plug in what we know 

a*(2a)=50 (we replaced "b" with "2a" because we know from the info they gave us that b=2a)

now solve for "a"

a*2a=50
2a²=50
a²=50/2
a²=25
√a²=√25
a=5

which because 2a=b we know that b=10 

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Which is bigger 31/100 or 5/10

What 6/8 turned into a decimal

Answers

You can simplify 6/8 to 3/4. 3/4 and 6/8 are both 0.75 as a decimal.

What number could make this equations have no value of x. 3x+8 = 3x + ?

Answers

Answer:

All values of x :-

  • 3x + 8 = 3x + 8 has Infinite solutions .

Just one value of X :-

  • 3x + 8 = 3x + x is equal to 3x + 8 = 4x , which has one solution at x= 8 .

Step-by-step explanation:

I hope this helps you !!

?= anything
this is because the slope is the slopes are the same in both equations so they will cancel each other.

What is 1/6 + (2/3 - 1/4) in simplest form

Answers

(1)/(6)+((2)/(3)-(1)/(4))=\ \ \ \ | make\ a\ common\ denominator\n\n(2)/(12)+(8)/(12)-(3)/(12)=(2+8-3)/(12)=(7)/(12)\n\n The\ simplest\ form \ is\ (7)/(12).

Connor went to New York for vacation. He spent 3 nights at a hotel and rented a car for 4 days. Jillian stayed at the same hotel, but spent 4 nights and rented a car for 5 days from the same company. If Connor paid $675 and Jillian paid $875, how much did one night at the hotel cost?

Answers

The answer for the question in problem would be $125 is the price of hotel per night. This is computed by establishing the equations from the given statements, 3x + 4y = 625 and 4x +5y = 875. And by substitution you would get the answer of 125 as the price per night n the hotel and 75 per day for the rental of car.

Answer:

The cost of one night at the hotel is $125

Step-by-step explanation:

Let the cost of each night spend in hotel is = $x

Let the cost of each day of car rented = $y

Cannor spent 3 nights at a hotel and rented a car for 4 days paid $675.

\Rightarrow3x+4y=675  ......(1)

Jillian also spent 4 nights in same hotel and rented a car for 5 days paid $875.

\Rightarrow4x+5y=875  .......(2)

Now, we solve equation (1) and (2) by substitution method

From (1) take the value of x,  x=(675-4y)/(3)

then put in equation (2)4*(675-4y)/(3)+5y=875

solve,

\Rightarrow 4*(675-4y)+5y*3=875*3  (Taking LCM)

\Rightarrow2700-16y+15y=2625

\Rightarrow y=2700-2625=75

Now, put value of y=75 in value of  x=(675-4y)/(3)

\Rightarrow x=(675-4(75))/(3)

\Rightarrow x=(675-300)/(3)

\Rightarrow x=(375)/(3)

\Rightarrow x=125

Therefore, the cost of one night at the hotel is $125


6 to the 2nd power ÷ 2(3) + 4

Answers

For this case we have the following expression:
 "6 to the 2nd power ÷ 2(3) + 4"
 Rewriting the expression in algebraic form we have:
 (6^2)/(2(3)+4)
 Rewriting the numerator we have:
 (36)/(2(3)+4)
 Rewriting the denominator we have:
 (36)/(6+4)
 (36)/(10)
 (18)/(5)
 Dividing both numbers we have:
 (18)/(5) = 3.6
 Answer:
 
The result of the given expression is: 
 
(6^2)/(2(3)+4)=3.6

6 to the second power means 6²

So,

6² ÷ 2 ( 3 ) + 4
 
=36/2(3)+4

=(18)(3)+4

=54+4

=58


Can you explain to me in steps how to work this problem
4(2x-2)-4=4(x-5)+32

Answers

4\left( 2x-2 \right) -4=4\left( x-5 \right) +32\n \n 8x-8-4=4x-20+32\n \n 8x-12=4x+12

\n \n 8x-4x=12+12\n \n 4x=24\n \n \frac { 1 }{ 4 } \cdot 4x=\frac { 1 }{ 4 } \cdot 24\n \n x=6
4(2x - 2) - 4 = 4(x - 5) + 32
4(2x) - 4(2) - 4 = 4(x) - 4(5) + 32
8x - 8 - 4 = 4x - 20 + 32
8x - 12 = 4x + 12
-4x       -4x       
4x - 12 = 12
     +12  +12
     4x = 24 
      4      4
       x = 6