CHEMISTRY HIGH SCHOOL

What is the molarity of a solution that is made by adding 57.3 g of MgO to 500.0 mL of solutions

Answers

Answer 1
Answer:

Answer:

The answer to your question is 2.84 M

Explanation:

Data

mass of MgO = 57.3 g

volume of the solution = 500 ml

Process

1.- Calculate the molar mass of MgO

MgO = 24.3 + 16 = 40.3 g

2.- Calculate the moles of MgO

                 40.3 g MgO ----------------- 1 mol

                  57.3 g MgO -----------------  x

                          x = (57.3 x 1) / 40.3

                          x = 1.42 moles

3.- Calculate the Molarity

Molarity = moles / volume (l)

Volume = 0.5 liters

-Substitution

Molarity = 1.42 / 0.5

-Result

Molarity = 2.84
Answer 2
Answer:

Final answer:

The molarity of the solution is 2.84 M.

Explanation:

To find the molarity of the solution, we need to first calculate the number of moles of MgO and the volume of the solution.

First, we convert the mass of MgO to moles using its molar mass. The molar mass of MgO is 40.31 g/mol, so:

moles of MgO = mass of MgO / molar mass of MgO

moles of MgO = 57.3 g / 40.31 g/mol = 1.42 mol

Next, we convert the volume of the solution to liters:

volume of solution = 500.0 mL / 1000 mL/L = 0.500 L

Finally, we divide the number of moles of MgO by the volume of the solution to find the molarity:

molarity = moles of solute / volume of solution

molarity = 1.42 mol / 0.500 L = 2.84 M

Learn more about Molarity here:

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