548.55 grams of aluminum hydroxide should theoretically form.
Explanation:
Balanced equation for the reaction:
3 NaOH + Al ⇒ Al(OH)3 +3 Na
DATA GIVEN:
mass of NaOH = 842 grams, atomic mass =39.9 grams/mole
mass of Al = 750 grams, atomic mass = 26.9 grams/mole
aluminum hydroxide theoretical yield = ?
Moles of NaOH reacted
number of moles =
putting the values in the equation
NaOH =
= 21.1 MOLES OF NaOH
Al =
= 27.8 moles
from the equation
from 3 moles of NaOH 1 mole of Al(OH)3 is produced
21.1 moles of NaOH will react to give x moles of Al(OH)3
=
7.03 moles of Al(OH)3 is formed.
and
1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction
so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH
mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)
= 548.55 grams
theoretical yield from the given data is 548.55 grams
The answer is 4.8 x 10^5 in scientific notation and 480,000 in standard form.
To multiplying numbers in scientific notation, you need to multiply the coefficients and add the exponents.
Using the given numbers, (1.2 x 107) and (4 x 10-2), we multiply the coefficients 1.2 and 4 to get 4.8.
Then, we add the exponents 7 and -2 to get 5.
Writing the result in scientific notation, we have 4.8 x 105.
In standard form, this is expressed as 480,000.
Therefore, the answer in scientific notation is 4.8 x 105 and in standard form is 480,000.
Learn more about multiplying numbers in scientific notation here:
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B) The attractive forces are stronger in a liquid
C) The attractive forces are stronger in a solid
D)The attractive forces of a solid allow the particle to move freely while the liquid molecules vibrate around a fixed point
Answer:
Option-C (The attractive forces are stronger in a solid)
Explanation:
The substance either exist as a Solid or Liquid depends upon on the following two factors;
ii) Kinetic Energy:
Greater the K.E of particles, greater will be the distance between the particles of a substance. In Liquids the K.E of particles is greater than the K.E of particles in Solid. Hence, the Liquid Particles separated by greater distance as compared to particles of Solids.
ii) Attractive Intermolecular Forces:
Greater the Attractive Intermolecular Forces between the particles of a substance, smaller will be the distance between the particles. As the distance between the particles in Solid state of substance are very small as compared to that of Liquids hence, it can be concluded that the Attractive Intermolecular Forces in Solids are stronger than Liquids.
Answer:
Yes
Explanation:
First of all, aromatic compounds are part of a group of compounds known as hydrocarbons. Hydrocarbons are compounds containing only gmhydrogen and carbon. Some aromatic compounds contain more than one benzene ring. These belong to another subgroup known as poly nuclear aromatic hydrocarbons.
Using a *MULTIMETER* is the best way to test and compare each fruit and vegetable. Because each fruits or vegetables all have different conductivity levels!
(Mark this as the brainliest if this helps!)
8, 14, 7
Answer:
it should be greater than 7 but equal to or less than 14
Explanation:
greater than 8 okay
Answer:
Concentration of NaOH= 0.0036 M
Explanation:
Given data:
Volume of HCl = 25 mL
Concentration of HCl = 0.05 M
Volume of NaOH = 345 mL
Concentration of NaOH = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Concentration of HCl
V₁ = Volume of HCl
C₂ = Concentration of NaOH
V₂ = Volume of NaOH
Now we will put the values in formula.
C₁V₁ = C₂V₂
0.05 M × 25 mL = C₂ × 345 mL
1.25 M.mL = C₂ × 345 mL
C₂ = 1.25 M.mL/345 mL
C₂ = 0.0036 M
To find the concentration of the NaOH solution, we can use the concept of titration. By using the equation Moles = Concentration * Volume, we can calculate the moles of HCl used and then use the ratio of moles between HCl and NaOH to find the concentration of the NaOH solution.
To find the concentration of the NaOH solution, we need to use the concept of titration. From the given information, it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution. We can use the equation Moles = Concentration * Volume to find the amount in moles of HCl used. Then, we can use this information to calculate the concentration of the NaOH solution.
First, let's calculate the moles of HCl used:
Moles of HCl = (0.05 M) x (0.025 L) = 0.00125 mol
Next, we can use the ratio of moles between HCl and NaOH, which is 1:1, to find the moles of NaOH in the solution:
Moles of NaOH = 0.00125 mol
Finally, we can calculate the concentration using the formula:
The concentration of NaOH = (0.00125 mol) / (0.345 L) = 0.00362 M
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