MATHEMATICS MIDDLE SCHOOL

A moving helper company gave Mike these two quotes. Use a system of equations todetermine the hourly rates for loading/unloading and packing/unpacking.

4 hours of

loading/unloading

7 hours of

loading/unloading

Answers

Answer 1

Answer:

The hourly rates of loading/unloading = $100

The hourly rates of packing/unpacking = $90

Step-by-step explanation:

Here, the given table is MISSING.

The correct table for reference is attached.

Now, let us assume the hourly rates of loading/unloading = $ m

Assume the hourly rates of packing/unpacking = $ n

As given in the table:

3 hours of loading/unloading + 2 hours of packing/unpacking costs = $480

⇒ 3 m + 2 n = 480

⇒ 2 n = 480 - 3 m .... (1)

5 hours of loading/unloading + 2 hours of packing/unpacking costs = $680

⇒ 5 m + 2 n = 680

⇒ 2 n = 680 - 5 m .... (2)

Now, solving for the values of m and n, we get:

480 - 3 m = 680 - 5 m

⇒ 5 m - 3 m = 680 - 480

⇒ 2 m = 200

or, m = 100

Now, 2 n = 680 - 5 m = 680 - 5 (100) = 180

⇒ n = 90

Hence, the hourly rates of loading/unloading = $ m = $100

The hourly rates of packing/unpacking = $ n = $90

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Plss help me with this

Answers

$Use:\na* b=b\cdot a\n\na^n* a^m=a^(n+m)\n-----------------------\n1^o\ -5x^5*\left(-(1)/(5)x^2\right)=\left[-5*\left(-(1)/(5)\right)\right]* (x^5* x^2)=\boxed{1x^7=x^7}\n\n2^o\ 2ab^2*\left(-(1)/(2)a^2b\right)=\left[2*\left(-(1)/(2)\right)\right]*(ab^2* a^2b)=\boxed{-1a^3b^3=-a^3b^3}$

$3^o\ (3)/(5)xy^2*\left(-(5)/(3)x^2y^3\right)=\left[(3)/(5)*\left(-(5)/(3)\right)\right]*(xy^2* x^2y^3)=\boxed{-x^3y^5}\n\n4^o\ xy*(-2x^2y)=[1*(-2)]*(xy* x^2y)=\boxed{-2x^3y^2}$

A running track in the shape of an oval is shown. The ends of the track form semicircles. A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 68 m and length of one straight edge 140 m. What is the perimeter of the inside of the track?

Answers

two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.

Length = 140 m ; Width = 68 m

Circumference of a circle = 2 π r
circumference of a cirlce = 2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52

length = 2 * 140 m = 280 m

perimeter of the oval = 213.52 m + 280 m = 493.52 m

Answer:

493.52

Step-by-step explanation:

What is the value of the expression 16 + 4 • 5 – 6 ÷ 2? A.
15

B.
14

C.
33

D.
22

Answers

c.33 because using the process of pemdas. 4×5 = 20. 16 + 20 - 6 ÷ 2. Then 6÷2 = 3. 16+ 20 - 3 = 33

80% of what number is 24

Answers

80% of 30 is 24.

Given,

80% of what number is 24.

Let the number be x,

Then,

80% of x = 24

80/100 of x = 24

x = 30

Thus the required number is 30.

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24* 80/100 = 24*8/10 = 19.2 is the answer.

9 is subtracted from 5 times 3 and 10 is added

Answers

The final answer is 16

What is subtraction?

The act or process of taking one number away from another is called subtraction.

How to now the final value after subtraction?

According to the problem,

9 is subtracted from 5 times 3 and 10 is added

This can be written as (5 x 3) + 10- 9

= 16

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The answer to “9 is subtracted from 5 times 3 and 10 is added” is 16.

The enrollment at Roosevelt high school is 1,045 students,which is 5 times the enrollment of Truman middle school how many students (s) are enrolled at Truman middle school?