Multiplying any number by 2, and then by 5, results in the final product ending in 0, regardless of what the initial number was.
The question is about the identification of the digit in the ones place when a number is initially multiplied by 2 and that product is further multiplied by 5. Firstly, we know that any number multiplied by 2 will either end in 0, 2, 4, 6, or 8. This is because all multiples of 2 are even. Secondly, consider the product of this number (which may end in 0, 2, 4, 6, 8) being multiplied by 5. Any number ending with any of these digits, when multiplied by 5, will result in the product ending with 0. Hence, regardless of the initial number, multiplying it by 2 and then by 5 will result in a final product whose digit in the ones place is 0.
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Answer: 300
Step-by-step explanation: