Answer:
1. p*(1-p)
2. n*p*(1-p)
3. p*(1-p)
4. 0
5. p^2*(1-p)^2
6. 57/64
Step-by-step explanation:
1. Let Ik denote the reward (possibly 0) given at time k, for k∈{1,2,…,n}. Find E[Ik].
E[Ik]= p*(1-p)
2. Using the answer to part 1, find E[R].
E[R]= n*p*(1-p)
The variance calculation is more involved because the random variables I1,I2,…,In are not independent. We begin by computing the following values.
3. If k∈{1,2,…,n}, then
E[I2k]= p*(1-p)
4. If k∈{1,2,…,n−1}, then
E[IkIk+1]= 0
5. If k≥1, ℓ≥2, and k+ℓ≤n, then
E[IkIk+ℓ]= p^2*(1-p)^2
6. Using the results above, calculate the numerical value of var(R) assuming that p=3/4, n=10.
var(R)= 57/64
Answer:
1.19 minutes
Step-by-step explanation:
First, subtract the $3 monthly fee:
16.09 - 3
= 13.09
Then, divide this by 11:
13.09/11
= 1.19
So, he was billed for 1.19 minutes
Answer:
y = -2
Step-by-step explanation:
To find the equation of the tangent we apply implicit differentiation, and then we take apart dy/dx
The equation is
implicit differentiation give us
But we know that
Hence, for the point (0,-2) and by replacing for dy/dx
Hence m=0, that is, the tangent line to the point is a horizontal line that cross the y axis for y=-2. The equation is:
y=(0)x+b = -2
HOPE THIS HELPS!!
In order to find the equation of the tangent line to the curve y²(y² - 4) = x²(x² - 5) at the point (0, -2), we will use the method of implicit differentiation. Here are the steps:
Step 1: Differentiate Each Side of the Given Equation with Respect to x
Applying the chain rule to differentiate y²(y² - 4) with respect to x gives:
2y*y'(y² - 4) + y²*2y*y' = d/dx [y²(y² - 4)]
The chain rule is also applied to differentiate x²(x² - 5) with respect to x, yielding:
2x(x² - 5) + x²*2x = d/dx [x²(x² - 5)]
Step 2: Equate the Two Expressions Found from Step 1 and Solve for y'
2y*y'(y² - 4) + y²*2y*y' = 2x(x² - 5) + x²*2x
This equation can be solved by isolating y' (the derivative of y with respect to x), which represents the slope of the tangent line.
Step 3: Use the Given Point (0, -2) to Find the Slope of the Tangent Line
Substitute x = 0 and y = -2 into the equation found in Step 2 to get the specific value for the slope at the given point.
Step 4: Use the Point-Slope Form of the Line to Write the Equation of the Tangent Line
The point-slope form of the line y - y₁ = m(x - x₁) can be used to write the equation of the tangent line. We substitute for x₁ and y₁ with the coordinates of the given point (0, -2), and m with the slope found from Step 3.
The resulting equation represents the tangent line to the curve at the given point (0, -2). Please note that the full calculation may result in a complex slope due to the nature of the given curve equation. Nonetheless, this process illustrates the application of implicit differentiation and the point-slope form of a line in finding the equation of a tangent line to a curve.
#SPJ3
o 53
o 133
o 127
o 47
Enter your answer in the box.
The group of 12 students will save$6by visiting the science center instead of the Zoo.
Science center fee :
Zoo Fee :
The difference in the total amount spent :
Therefore, the group will save $6 by visiting the science center.
Learn more : brainly.com/question/18109354
ANSWER:
$6
ExPLANATION:
Step 1:
36.75 × 4 = 147
Step 2:
51 × 3 = 153
Step 3:
153 - 147 = 6
Solve: x - 1 < 3
x < 4
given x - 1 < 3 ( add 1 to both sides )
x < 4
or x ∈ ( - ∞, 4 ) ← in interval notation