7) 2(2x + 4) – 3(x - 1) = 11

Answer:

Time taken would be = 12 minutes to print the payroll if both computers are used

Step-by-step explanation:

Computer A Takes = 20 minutes

Computer B Takes = 30 minutes

To Find:

Time to print if both were used = ?

Solution :

Now We will first calculate How much work is done by each computer in one minute

Computer A will do = 1/20 Work one minute

Computer B will do  = 1/30 work in one minute

Now if both computers are used then

work done by both of them in one minute would be sum of both the computers f the work together

So

it would be

Work done =

Taking LCM and solving

Work done =

                   =

                   =

Now to do the whole task Time taken would be reciprocal of Work done in one minute

So

Time taken would be = 12 minutes

Answer: It would take 52 minutes

Step-by-step explanation:

20+32=52

Answer:

D. Triangle is correct

Step-by-step explanation:

We are given that,

A polygon is rotated to form the blue block patterns,

As, from the figure, we see that,

The polygon being rotated has three sides.

So, the polygon is a triangle.

Thus, a triangle is rotated to form the blue block pattern.

Hence, option D is correct.

Answer:

The answer is D) Triangle

Answer:

  see below for the graph

Step-by-step explanation:

The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.

Here's one way to get there.

__

Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.

Now, it is ...

  f(x) = |x| -1

We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.

Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...

  g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5

This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:

  x = -(5/3)|y| +5

______

Comment on this answer

Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.