MATHEMATICS MIDDLE SCHOOL

A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice, he lost 10 1/4 pounds, and during the second week he lost another 3 1/2 pounds. How much did he weigh at that point?A: 182 1/3 lb
B: 181 1/2 lb
C: 182 5/12 lb
D: 183 2/3 lb

Help please?

Answers

Answer 1

Answer:

We need to find the weight of a person at a certain period of time.

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

Initial weight of person = $170(2)/(3)$ pounds.

Weight gained = $25(5)/(12)$ pounds

Weight lost = $10(1)/(4)+3(1)/(2)$ pounds

So, weight of the person is

$170(2)/(3)+25(5)/(12)-(10(1)/(4)+3(1)/(2))\n =170+(2)/(3)+25+(5)/(12)-(10+(1)/(4)+3+(1)/(2))\n =195+(8+5)/(12)-13-(1+2)/(4)\n =182+(13)/(12)-(3)/(4)\n =182+(13-3)/(12)\n =182+(10)/(12)\n =182+(1)/(3)=182(1)/(3)$

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

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Answer 2

Answer:

Answer:

182 1/3 lbs

MAY: weight = 170 2/3

Summer: gained 25 5/12

New weight : 170 2/3 + 25 5/12

Get a common denominator of 12

170 2/3 *4/4 + 25 5/12

170 8/12 + 25 5/12 = 195 13/12

The he lost 10 1/4 during the first week of fall practice

195 13/12 - 10 1/4

We need to get a common denominator of 12

195 13/12 - 10 1/4*3/3

195 13/12 - 10 3/12

185 10/12

The he lost another 3 1/2 pound during the second week

185 10/12 - 3 1/2

We need to get a common denominator of 12

185 10/12 - 3 1/2 * 6/6

185 10/12 - 3 6/12

182 4/12

Simplify the fraction

182 1/3 lbs

Hope this helps!

have a great day! :))))))

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