Given:
Quadrilateral PQRS is a rhombus.
To find:
The value of y.
Solution:
In the rhombus PQRS,
PS = 10y and SR = y + 45
Property of rhombus:
All sides are congruent.
⇒ PS = SR
⇒ 10y = y + 45
Subtract y from both sides.
⇒ 10y - y = y + 45 - y
⇒ 9y = 45
Divide by 9 on both sides.
⇒ y = 5
The value of y is 5.
The lines 2x + ky = 3 and kx + 8y = 7 intersect for all values of k except 4 and -4 the answer is R - {4, -4}.
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
Two linear equations in two variables are:
2x + ky = 3 and
kx + 8y = 7
As we know the condition for the lines to intersect or have unique solutions:
2/k ≠ k/8
After cross multiplication:
k² ≠ 16
k ≠ ±4
The values of k can be anything except 4 and - 4
Thus, the lines 2x + ky = 3 and kx + 8y = 7 intersect for all values of k except 4 and -4 the answer is R - {4, -4}.
Learn more about the linear equation here:
#SPJ2
Answer:
ky=3-2x
y=(3-2x)/k
y=(7-kx)/8
(3-2x)/k=(7-kx)/8
8(3-2x)=(7-kx)k
24-16x=7k-k*kx
24=7k-kkx+16x
24+7k=kkx+16x
24+7k=x(k^2+16)
Answer:
y = (1/3)x
Step-by-step explanation:
If this is truly a line, then we can find its equation using any two of the three given points. If we go from (3, 1) to (27, 9), x increases by 24 and y increases by 8. Thus, the slope of this line is m = rise / run = 8 / 24, or m = 1/3.
Using the point (3, 1) and the slope m = 1/3, the slope-intercept form y = mx + b becomes 1 = (1/3)(3) + b. Thus, b = 0, and the line is y = (1/3)x.
Answer:
y=x ~apex
Step-by-step explanation:
B.
1/3
C.
square root of 4
D.
Square root of 6
y = -6x+32
O A. (2,5)
O B. (8,4)
O C. (4,8)
O D. (0,2)
Answer: the answer is indeed (4,8)
Step-by-step explanation:
A. 15x+1.25=20
B. 1.25x+15=20
C. 1.25x-15=20
D. 15x-1.25=20