MATHEMATICS MIDDLE SCHOOL

Which is the best to buy?A) 16 oz of hand soap for $2.40

B) 20 oz of Hand soap for $2.80

C) 24 oz of hand soap for $3.00

D) 12 oz of hand soap for $2.00

Answers

Answer 1
Answer:

Answer: C

You want to find out the cost per ounce.

A:

2.4/16 = 15 cents per oz

B:

2.8/20 = 14 cents per oz

C:

3/24 = About 13 cents per oz  (0.125)

D:

2/12 = About 17 cents per oz (1.66666667)

The cheapest one is C, about 13 cents per oz.

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Please help with some probelms! Check some too the questions that has a blue dot are the answers please check that please!
Which expression is equivalent to this one?–5(6 + 11)A.(–5) • 6 + 11B.(–5) + 6 + 11C.(–5) • 6 • 11D.(–5) • 6 + (–5) • 11

Solve by looking for the X

Answers

Answer:

It is a

Hope this helps you

What is negative 7 over 12 plus 7 over 10?

Answers

Step-by-step explanation:

all work is shown and pictured

*WILL GIVE BRAINLIEST* Simplify (5.29 x 10^9) divided by (9.32 x 10^-7). Write in Scientific Notation.

Answers

5.6759656652361 × 10^15

Answer: Using the corrected exponents on the reposted question:. D is the choice.

5.676×10-³

Step-by-step explanation:

5.29÷9.32=0.567596 That would be equivalent to 5.676×10-¹, like 1/0 of 5.676.

Then to calculate 10 ^-9 divided by 10^-7, we subtract the -7 from -9. -9 -(-7) = -2

That leaves us with 10-² × 10-¹ so adding the exponents we have 10-³ to multiply by 5.676 for the scientific notation.

Where was 5/6 of a pie. Joe ate 1/6 of the pie. How much of the whole pie was left?

Answers

 5/6 minus 1/6 is equal to 4/6. Good luck :)
4/6 of the pie was left:)
since the denominators are the same
the bottom numbers or in this case the number 6 in the fraction:)
all you have to do is subtract 5-1 = 4!!
so keep your denominator the same and add the new numerator
4
--
6

hope i helped!

Simple question 

Derivative of \boxed{f(y)= (y^2)/(y^3+8) }

Answers

Let's go ;D

f(y)=(y^2)/(y^3+8)

we have to use the quotient rule.

f(y)=(g(y))/(h(y))

f'(y)=(h(y)*g'(y)-g(y)*h'(y))/([h(y)]^2)

Then

g(y)=y^2

g'(y)=2y

h(y)=y^3+8

h(y)=3y^2

Now we can replace

f'(y)=(h(y)*g'(y)-g(y)*h'(y))/([h(y)]^2)

f'(y)=((y^3+8)*2y-(y^2)*3y^2)/((y^3+8)^2)

f'(y)=(2y^4+16y-3y^4)/((y^3+8)^2)

\boxed{\boxed{f'(y)=(16y-y^4)/((y^3+8)^2)}}

!!!!!!!!!!!!!!!!!! Help!!!

Answers

5. The value is 10,000.
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