Why is freshly distilled or deionized water used in this standardization?

Answers

Answer 1
Answer:

Answer:

The amount of carbon dioxide is little in deionized water.

Explanation:

Deionized water is a water with little or no impurities. Impurities are in waters are not able to boil below or above the boiling point of water,and in this case are been retained in the original container.

Answer 2
Answer:

Answer:

There is little CO2 in freshly deionized or distilled water.

Explanation:

Freshly distilled water has no hydrogen peroxide. Distilled water contains calcium, which stabilizes the sodium hydroxide , Freshly deionized water has a pH of 4.72. There is little CO2 in freshly deionized or distilled water.


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Calculate the force needed to bring a 1,019-kg car to rest from a speed of 29 m/s in a distance of 118 m

Answers

Acceleration = ▵v/▵t
Time = d/v
Fisrt calculate time : ( 118/29 ) = 4 seconds
Then calculate acceleration
A = 29/4 = 7.25 m/s²
Now the force.
Force = mass * acceleration.
F= 1,019 * 7.25
F= 7,387 N

Explain why a light wave refracts when it travels through mediums such as air to water.

Answers

The simplest explanation is that the speed changes. That causes the wavefront to change direction and so refraction takes place.

Two objects are connected by a light string that passes over a frictionless pulley as shown in the figure below. Assume the incline is frictionless and take m1 = 2.00 kg, m2 = 7.35 kg, and θ = 50.0°.1) Find the magnitude of the accelerations of the objects. (m/s^2)
2)Find the tension in the string. (N)
3)Find the speed of each object 2.50 s after being released from rest. (m/s)

Answers

Answer:

Part a)

a = 3.81 m/s^2

Part b)

T = 27.2 N

Part c)

v_f = 9.53 m/s

Explanation:

For m2 mass along the inclined plane we can write

m_2g sin\theta - T = m_2 a

for m1 mass we can write equation in vertical direction

T - m_1 g = m_1 a

so we will have

m_2g sin\theta - m_1g = (m_1 + m_2) a

so we have

a = ((m_2 sin\theta - m_1)g)/(m_1 + m_2)

now plug in all data in it

a = ((7.35 sin50 - 2)9.81)/(7.35 + 2)

a = 3.81 m/s^2

Part b)

from above equation

T = m_1g + m_1 a

T = 2(9.81 + 3.81)

T = 27.2 N

Part c)

Speed of the object after t = 2.50 s

v_f = v_i + at

v_f = 0 + 3.81(2.50)

v_f = 9.53 m/s

assume m1 moving down, so m2 is moving up and accelleration direction of each box is the same as its movement.

check forces act on m1
1. tension of the rope T up
2. m1g down
3. moving down with a
f = ma --> m1g - T = m1a ...(1)
or. T = m1g - m1a ... (1.1)

check forces act on m2
1. tension of the rope T up alone the incline. it must be equal to previous one because it is the same segment of the rope.
2. m2gsine(θ) down along the incline
3. moving up with a
f = ma --> T - m2gsine(θ) = m2a ...(2)

replace T from (1.1) to (2)
(m1g - m1a) - m2gsin(θ) = m2a
m1g - m2gsin(θ) = m2a + m1a
a = g(m1 - m2sin(θ))/(m1 + m2)

plug in value you will get the answer. if a is negative, it means direction on our assumption is not correct. it's the opposite (direction).

after get a, you will get T
and velocity use v = u + at

... i cannot post pict. draw the diagram will make you understand this better.

What is the difference between a homogeneous mixture and heterogeneous mixture?

Answers

Homogenous mixtures don't have visible constituents. An example of this would be water.

Heterogenous ones have visible constituents and an example would be if you put some dirt in water and then it wouldn't mix properly and you could see the dirt in it.

4. A 1500 kg car is rolling at 2.0 m/s. You would like to stop the car by firing a 10 kg blob ofsticky clay at it. How fast should you fire the clay?

Answers

The clay must be 300 m/s fast in other to stop the car.

For the car to stop, The momentum of the car must be equal to the momentum of the clay.

Formula:

  • MV = mv................. Equation 1

Where:

  • M = mass of the car
  • V = Velocity of the car
  • m = mass of the clay
  • v = velocity of the clay

Make v the subject of the equation.

  • v = MV/m................... Equation 2

From the question,

Given:

  • M = 1500 kg
  • V = 2 m/s
  • m = 10 kg

Substitute these values into equation 2

  • v = 1500(2)/10
  • v = 300 m/s.

Hence, The clay must be 300 m/s fast in other to stop the car.

Learn more about momentum here: brainly.com/question/7973509

Final answer:

To stop the car rolling at 2.0 m/s with a blob of clay, you should fire the blob of clay at a speed of 300 m/s. This is based on the principle of conservation of momentum.

Explanation:

The question involves a principle of Physics called the law of conservation of momentum. The law states that the total momentum of a system remains constant if no external forces act on it. Here, the car and the clay are the two objects in the system.

At the start, only the car has momentum, which can be calculated with the equation: momentum = mass x velocity => momentum of car = 1500 kg x 2 m/s = 3000 kg m/s.

After the clay is fired at the car, the total momentum of the system (car + clay) still remains 3000 kg m/s, but now the momentum is shared between them. We want to stop the car, so it will now have no momentum, meaning all momentum must be with the clay.

The equation again turns to momentum = mass x velocity => velocity = momentum/mass => velocity of clay = 3000 kg m/s / 10 kg = 300 m/s.

You should fire the clay at 300 m/s to stop the car.

Learn more about the Law of Conservation of Momentum here:

brainly.com/question/33316833

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Identify some common fuels

Answers

On a worldwide scale, the most common fuels are wood, grass, peat, coal, and animal fats and oils.
Coal, Wood, Petroleum, Natural Gas, Kerosene, Diesel, LPG (Liquefied Petroleum Gas), CNG (Compressed Natural Gas), Coke etc. are some commonly used fuels.