Answer:
The slope is m=2.5 $/movie
Step-by-step explanation:
The slope of the graph could be found using any two points y and the equation for slope of a line, which is
So, we select the points y , and we replace the values in the equation for slope,
And in this case, represents the cost to rent one movie.
Answer: The slope of the graph is 2.50, and it represents the cost of each movie
Step-by-step explanation:
Pls help
Answer:
linne b
Step-by-step explanation:
you can see that on the x axis at point 3 you can go 4 up until the line B is met
Answer:
9 and 3.35 respectively
Step-by-step explanation:
Mean=Sum of data÷No. of data
=(3+5+6+9+11+12+17)÷7
=63÷7
=9
Standard Deviation=√{(sum of squares of data÷no. of data)-(sum of data÷no. of data)
=√(705÷7)-(63÷7)
=√100.71÷9
=√11.19
=3.35
Answer:
9 M
Step-by-step explanation:
a^2+b^2=c^2
12^2+b^2=15^2
144+b^2=225
-144 -144
b^2=81
b=sqrt of 81
b=9
The coordinates of vertex B′ are ____ .
The coordinates of vertex C′ are ____.
Answer:
A'(1, 1); B'(3, 2); C'(1, 2)
Step-by-step explanation:
The original points are A(1,1 ), B(2, 3) and C(2, 1).
Reflecting the triangle across the x-axis will negate every y-coordinate; this maps
(1, 1)→(1, -1); (2, 3)→(2, -3); (2, 1)→(2, -1)
Rotating the figure 90° clockwise about the origin switches the x- and y-coordinates and negates the x-coordinate; this maps
(1, -1)→(-1 -1); (2, -3)→(-3, -2); (2, -1)→(-1, -2)
Reflecting across the line y=x will negate both the x- and y-coordinates; this maps
(-1, -1)→(1, 1); (-3, -2)→(3, 2); (-1, -2)→(1, 2)
To find the coordinates of ∆ABC after reflection across the x-axis, rotation by 90°, and reflection across y = x, we would apply these transformations to each point. Initially reflected across x-axis results in (x, -y), the 90° rotation gives (-y, x), and final reflection over y = x gives (x, -y). To find A′B′C′ we would need original coordinates, but general rule follows this pattern.
In this mathematics problem, we will find the coordinates for vertex A′, B′, and C′ of ∆A′B′C′. Given a triangle ∆ABC reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the line y = x, we need the original coordinates of A, B, and C to find A′B′C′. However, if we take a generic point (x, y), we can assume the following:
Assuming these transformations, we can find the final coordinates for A′, B′, and C′.
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