MATHEMATICS HIGH SCHOOL

ABCD is a rectangle. Find the length of each diagonals.

AC = c over 3
BD = 4 - c

Answers

Answer 1
Answer: Diagonals are congruent

|AC| = |BD|

(c)/(3)=4-c\ \ \ |multiply\ both\ sides\ by\ 3\n\n\not3^1\cdot(c)/(\not3_1)=3(4)-3c\n\nc=12-3c\ \ \ |add\ 3c\ to\ both\ sides\n\n4c=12\ \ \ \ |divide\ both\ sides\ by\ 4\n\n\boxed{c=3}\n\n|AC|=|BD|=(3)/(3)=1

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Which of the following are true statements about the expression 5 + (-5) 1. the expression equals 0. 2. The expression equals 10. 3. The expression describes the number that is 5 to the left of 5 on the number line. 4. The expression describes the number that is 5 to the right of 5 on the number line.
What is the simplified expression for 5 a b + 9 a b minus a b?

Could this set of numbers represent the lengths of the sides of a right triangle? {5,9,13}

Answers

Answer:

Yes, it can

Step-by-step explanation:

Yes, the set of numbers {5, 9, 13} can represent the lengths of the sides of a right triangle. This set of numbers follows the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case:

The length of one side is 5.

The length of the other side is 9.

The length of the hypotenuse is 13.

You can check if these numbers satisfy the Pythagorean theorem:

5^2 + 9^2 = 25 + 81 = 106

13^2 = 169

The set of numbers {5, 9, 13} does represent the lengths of the sides of a right triangle, as it satisfies the Pythagorean theorem.

I have to rewrite an equation so that y is a function of x. I think I'm solving for Y, because on my examples it has "y=". How do I do this?

Answers


You do whatever you need to do to one side of the equation in order to have
only ' y ' left on that side, AND every time you do something to that side of
the equation, do exactly the same thing to the other side.

Here are three examples, out of the 9 answers you want handed to you:

#16:                                  3x + 5y = 7

Subtract  3x  from each side:      5y = -3x + 7

Divide each side by  5 :                y = -3/5 x + 7/5

======================================

#17:                                     13 = 12x - 2y

Add  2y  to each side:    2y + 13 = 12x

Subtract 13  from each side:  2y = 12x - 13

Divide each side by  2 :          y = 6x - 13/2

======================================

#22:                                1/4 y + 3 = -5x

Subtract  3  from each side:   1/4 y = -5x + 3

Multiply each side by  4 :            y = -20x + 12

Which is bigger 8/10 or 79/100

Answers

To figure this out first we will convert each fraction in to a decimal. To do this we need to divide the numerator by the denominator. 

8/10 = 8 ÷ 10 = 0.80

79/100 = 79 ÷ 100 = 0.79

So, 8/10 = 0.80 & 79/100 = 0.79.

Since 0.80 is more than 0.79 8/10 is bigger.

So 8/10 (0.80) is bigger than 79/100 (0.79). 

Hope I helped ya!! :) 
you can say 8/10 = 80/100 ⇒ 80/100 is bigger than 79/100 :)))

A dinner bill of $31.37 had 6% tax added to that total

Answers

33.25 is the answer.
is there a question to the problem

What is -5/8 + 3/4 ?

Answers

Answer:

0.125

Step-by-step explanation:

Solve the system of equations using substitution.
3x + 2y = 7
y = –3x + 11

Answers

3x + 2y = 7
y = -3x + 11

Solve the system of equation using substitution.

Substitute the y in the first equation by its value presented in the 2nd equation.

3x + 2y = 7
3x + 2(-3x + 11) = 7
3x - 6x + 22 = 7
-3x + 22 = 7
-3x = 7 - 22
-3x = -15
-3x/-3 = -15/-3
x = 5

Substitute x in the 2nd equation by its computed value. x = 5
y = -3x + 11
y = -3(5) + 11
y = -15 + 11
y = -4

x = 5 ; y = -4

Substitute x and y in the 1st equation with its corresponding values

3x + 2y = 7
3(5) + 2(-4) = 7
15 - 8 = 7
7 = 7
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