Paul works for a company that deals in paints and dyes. He is paid a fixed monthly salary plus 15 percent commission on monthly sales over $20,000.

Answers

Answer 1
Answer: If x is the sales amount over $20,000, the function g(x) giving Paul's commission is 0.15x

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What is the value of A for the exponential function in the graph represented in the form of f(x) = a(bx)?

Answers

Answer:

a = 3

Step-by-step explanation:

f(x) = a(bˣ)

At x = 0

f(0) = a(b⁰)

f(0) = a(1)

f(0) = a

From the graph

f(0) = 3

Therefor

a = 3

It takes 10 minutes to bake a batch of cookies. You need to bake 7 batches of cookies. How long will it take to bake all the cookies?

Answers

You know 1 batch of cookies = 10 minutes

Now, 7 batch of cookies = ? 
To do this just do 7×10=70.
So the answer is 70 minutes = 7 batch of cookies. 

You can also set up a proportion. 

10       x
__ = ____
1         7 

Cross multiply and 7×10=70 and 10x. So now its like this. 
70= 10x 
  ÷10 ÷10
_________
7=x

So the answer is 7. 

 

A function is created to represent the balance on a credit card each month. What restrictions would be made to the range

Answers

Answer:

The range would include all real numbers.

Step-by-step explanation:

Consider the provided information.

Range of a function is the set of output values which a function can produce.

Let say we created a function to represent the balance on a credit card each month. Then the range will be the balance amount.

The balance amount can be a negative number as we are talking about credit card, also the balance can be zero or a positive number.

The credit card balance can be in decimals.

Thus, the balance can be any real number.

Hence, the range would include all real numbers.

It could include any numbers any real numbers.

If t is any real number, prove that 1+(tant)^2=(sect)^2

Answers

1+\left(tant\right)^2=\left(sect\right)^2\n\nL=1+\left((sint)/(cost)\right)^2=1+(sin^2t)/(cos^2t)=(cos^2t)/(cos^2t)+(sin^2t)/(cos^2t)=(cos^2t+sin^2)/(cos^2t)=(1)/(cos^2t)\n\n=\left((1)/(cost)\right)^2=(sect)^2=R\n\n====================================\n\n\ntanx=(sinx)/(cosx)\n\nsin^2x+cos^2x=1\n\nsecx=(1)/(cosx)

The sum of the ages of Arturo, Benny, and Carlos is 41 years. Twice Arturo's age exceeds the sum of Benny and Carlos's ages by one year. Five years ago, Benny was 2 years more than twice as old as Carlos. Find their ages now

Answers

Answer: Arturo is 14 years

Benny is 17 years

Carlos is 10 years

Step-by-step explanation:

Let x represent the age of Arturo.

Let y represent the age of Benny.

Let z represent the age of Carlos.

The sum of the ages of Arturo, Benny, and Carlos is 41 years. It means that

x + y + z = 41- - - - - - - - - - - - -1

Twice Arturo's age exceeds the sum of Benny and Carlos's ages by one year. It means that

2x = y + z + 1- - - - - - - - - 2

Five years ago, Benny was 2 years more than twice as old as Carlos. It means that

y - 5 = 2(z - 5) + 2

y - 5 = 2z - 10 + 2

y = 2z - 8 + 5

y = 2z - 3

Substituting y = 2z - 3 into equation 2, it becomes

2x = 2z - 3 + z + 1

2x = 2z + z - 3 + 1

2x = 3z - 2

x = 3z/2 - 1

Substituting y = 2z - 3 and

x = 3z/2 - 1 into equation 1, it becomes

3z/2 - 1 + 2z - 3 + z = 41

Multiplying through by 2, it becomes

3z - 2 + 4z - 6 + 2z = 82

3z + 4z + 2z - 2 - 6 = 82

9z - 8 = 82

9z = 82 + 8 = 90

z = 90/9

z = 10

x = 3z/2 - 1 = (3 × 10)/2 - 1

x = 14

y = 2z - 3 = 2 × 10 - 3

y = 17

The variable a is the length of the ladder. The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom. Suppose that the length of the ladder is 5.0 meters and the top is sliding down the wall at a rate of 0.4 m/s. Calculate dx dt when h = 3.1.

Answers

Answer:

dx/dt= 0.2608 at  h= 3.1 m

Step-by-step explanation:

a is the length of the ladder. a=5

by pythagorus theorem

x^2 = a^2-h^2

differentiating with respect to t we get

x(dx)/(dt) = -h(dh)/(dt)......1

The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom

At h= 3.1

x^2= 6^2-3.1^2 = 9.1×2.9

x= 5.1371 m

given (dh)/(dt) =-0.4

putting values in 1 to get dx/dt

5.1371(dx)/(dt) = 3.1×04.

dx/dt= 0.2608 at  h= 3.1 m

Answer:

(dx)/(dt) = 0.3

Step-by-step explanation:

The given situation forms a right triangle. We have to use the Pythagorean theorem's statement to solve this problem.

The theorem states that the sum of the squares of the legs is equal to the square of the hypotenuse.

Here Hypotenuse = length of the ladder (a)

Legs are h and x.

So, using the Pythagorean theorem, we get

a^2 = h^2 + x^2 -------------(1)

We are given a = 5 meters, (dh)/(dt) = 0.4

Now plug in a = 5 in the above equation, we get

5^2 = h^2 + x^2

25 = h^2 + x^2 -----(2)

To find the (dx)/(dt) . Differentiate the above equation with respective to the time t, we get

2h(dh)/(dt) + 2x(dx)/(dt) = 0\n -------(3)

We know that h = 3.1 and (dh)/(dt) = 0.4.

We can find x, by plug in h = 3.1 from the equation (2)

25 = 3.1^2 + x^2

x^2 = 25 - 9.61

x = 3.9

Now plug h = 3.1, x = 3.9 and (dh)/(dt) = -0.4 in the derivative (3) and find dx/dt

Here we represents  (dh)/(dt) = -0.4 because it is sliding down

2(3.1)(-0.4) + 2(3.9) (dx)/(dt) = 0

-2.48 + 7.8  (dx)/(dt)  = 0

7.8 (dx)/(dt)  = -2.48

(dx)/(dt)  = -2.48 ÷ -7.8

(dx)/(dt) = 0.3179

When we rounding off to the nearest tenths place, we get

(dx)/(dt) = 0.3