Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dA R , where R is the region in the first quadrant between the circles with center the origin and radii 2 and 4

Answer:

11.725%

Step-by-step explanation:

Given that :

True value = 0.904 seconds

Measured time = 1.010 seconds

Experimental error :

(|measured value - True value | / true value) * 100%

(|1.010 - 0.904| ÷ 0.904) * 100%

= 0.106 / 0.904 * 100%

= 0.1172566 * 100%

= 11.725%

Answer:

11.725%

Step-by-step explanation:

Answer:

The 90% confidence interval is (1408.325 hours, 2115.675 hours).

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which s is the standard deviation of the sample. So

The lower end of the interval is the mean subtracted by M. So it is 1762 - 353.675 = 1408.325 hours.

The upper end of the interval is the mean added to M. So it is 6.4 + 0.3944 = 2115.675 hours.

The 90% confidence interval is (1408.325 hours, 2115.675 hours).

The interval level of measurement is a number scale that classifies both order and the value change between each number. For example, a ruler has intervals 1, 2, and 3 inches. The distance between 1 to 2 inches is the same as the distance between 3 to 4 inches.

Answer:

No, the manager is not correct based on the 95% confidence interval.

Step-by-step explanation:

We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .

The Pivotal quantity for 95% confidence interval is given by;

                ~

where, X bar = sample mean = $1080

                s  = sample standard deviation = $260

                 n = sample size = 35 {five-week}

So, 95% confidence interval for average daily revenue, is given by;

P(-2.032 < < 2.032) = 0.95

P(-2.032 < < 2.032) = 0.95

P(-2.032 * < < 2.032 * ) = 0.95

P(X bar - 2.032 * < < X bar + 2.032 * ) = 0.95

95% confidence interval for = [ X bar - 2.032 * , X bar + 2.032 * ]

                                            = [ 1080 - 2.032 * , 1080 + 2.032 * ]

                                             = [ 990.70 , 1169.30 ]

No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.

Therefore, the store manager believe is not correct.

Final answer:

The 95% confidence interval for the store's average daily revenue is calculated to be approximately ($993.97, $1166.03). Since $1200 is outside this interval, the manager's belief that the coffee and pastry strategy will lead to an average daily revenue of $1200 is not backed by this confidence level.

Explanation:

In the field of statistics, a confidence interval (CI) is a type of interval estimate that is used to indicate the reliability of an estimate. The method for calculating a 95% confidence interval for the average daily revenue involves the sample mean, the standard deviation, and the z-score associated with a 95% confidence level, which is approximately 1.96. Let's use the provided data to calculate:

• Calculate the standard error by dividing the standard deviation by the square root of the sample size. Here, the standard deviation is $260, and the sample size is 5 weeks * 7 days/week = 35 days. So, the standard error is $260 / sqrt(35) = $43.89.
• Multiply the standard error by the z-score to get the margin of error. So, $43.89 * 1.96 = $86.03.
• Calculate the lower and upper bounds of the 95% confidence interval by subtracting and adding the margin of error from/to the sample mean. So, ($1080 - $86.03, $1080 + $86.03) = ($993.97, $1166.03).

The range of this 95% confidence interval is from $993.97 to $1166.03. This means we are 95% confident that the true average daily revenue lies within this interval. Since $1200 lies outside this interval, the manager's belief is not supported by this confidence interval.

Learn more about Confidence Interval here:

brainly.com/question/34700241

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Answer:

The correct answer is A.  The probability of randomly selecting a daisy from Bouquet S is less than the probability of randomly selecting a daisy from bouquet T.  

Step-by-step explanation:

We are told that Bouquet S contains 30 flowers and 13 of those flowers are daisies.   Therefore, the probability of selecting a daisy from Bouquet S can be modeled by:

13/30, which is greater than 1/3 but less than 1/2

We are also told that Bouquet T contains 13 flowers and 13 daises.  From this information, we can conclude that all of the flowers in Bouquet T are daises, or the probability can be modeled by:

13/13 = 1

Therefore, because the probability of selecting a daisy from Bouquet S is 13/30 and the probability of selecting a daisy from Bouquet T is 1, we can conclude that, as option A states, the probability of selecting a daisy from Bouquet S is less than the probability of selecting a daisy from Bouquet T.

Hope this helps!

Answer:

I believe the answer is A.

Step-by-step explanation:

If there are 13 daises per bouquet, that means one bouquet is all daises. The other bouquet has 30 flowers. 30-13 is 17 which means there are 17 other flowers rather than daises. 17 is greater than 13 by 4 which is not that  much. Therefore I think the answer is letter A.

Answer:

Step-by-step explanation:

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