Answer:
They have similar chemical properties
Explanation:
Hi, those elements all belong to the Group I of the periodic table meaning that they share not only similar electronic configuration (1 electron of valence) but also they have similar chemical properties, being those more marked the higher the atomic number.
The concentration of hydroxideions in the given aqueous solution is equal to 6.3 ×10⁻³ M.
pOH can be calculated from the negative logarithm of the concentration of hydroxideions in the given aqueous solution.
Mathematically, the formula of the pOH can be represented as shown below:
pOH = - log ([OH⁻ ])
and pH + pOH = 14 ..............(1)
Where [OH⁻] is representing the concentration of hydroxide ions in an aqueous solution.
Given, the value of the pH of the ammonia solution, pH = 11.8
Substitute the value of the pH in equation (1):
pH + pOH = 14
11.8 - log [OH⁻] = 14
- log [OH⁻] = 14 -11.8
log [OH⁻] = - 2.2
[OH⁻] = 6.3 × 10⁻³ M
Therefore, the concentration of the hydroxideions is equal to 6.3 ×10⁻³ M.
Learn more about pOH, here:
#SPJ5
(1) At STP, carbon has a greater density than
fluorine.
(2) A carbon atom has more valence electrons
than a fluorine atom.
(3) The difference in electronegativity between
carbon and oxygen is greater than that
between fluorine and oxygen.
(4) The difference in first ionization energy
between carbon and oxygen is greater than
that between fluorine and oxygen.
Answer: (3) The difference in electronegativity between carbon and oxygen is greater than that between fluorine and oxygen.
Explanation: Polarity of a molecule is due to the difference in electronegativity of the atoms. More is the electronegativity difference, more is the polarity.
Electronegativity of carbon = 2.5
Electronegativity of oxygen = 3.5
Electronegativity of fluorine = 4.0
Thus the difference in electronegativity of carbon and oxygen is=(3.5-2.5)= 1.0
Thus the difference in electronegativity of fluorine and oxygen is=(4.0-3.5)= 0.5.
Thus C-O bond is more polar than F-O bond.