What is the greatest common factor of 12x^3 - 9x^2?A) 3x

B) 6x

C) 3x^2

Answers

Answer 1
Answer:

Answer:the answer is C 3x^2

Step-by-step explanation:

Answer 2
Answer:

Final answer:

The greatest common factor of 12x^3 - 9x^2 is 3x^2.

Explanation:

The greatest common factor (GCF) of 12x^3 - 9x^2 can be found by factoring out the common factors of the terms. In this case, both terms have a common factor of 3x^2. By factoring out 3x^2, we get:

12x^3 - 9x^2 = 3x^2(4x - 3)

Therefore, the greatest common factor is 3x^2 (option C).

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Use the circle graph to determine how many hours per day Becky spends on each activity.School:____ Hours School= 25%
Eating:_____Hours Eating= 10%
Sleep:______Hours Sleep: 40%
Homework:____Hours Homework= 10%
Free Time:_____ Hours Free Time= 15%

Answers

404 error: graph not found

anyway, the graph was not included. since the sleep time was included, I will assume that the circle graph is worth 24 hours

all we need to do is to convert the percentages to fractions and multiply that by 24 to find out how many hours per activity


percent means parts out of 100 so x%=x/100


so we have
School
Eating
Sleep
Homework
Free Time

School=25%
25%=25/100=1/4
1/4 times 24=6
School: 6 hours


Eating=10%
10%=10/100=1/10
1/10 times 24=2.4
Eating: 2.4 hours


Sleep=40%
40%=40/100=4/10=2/5
2/5 times 24=48/5=9.6
Sleep: 9.6 hours


Homework=10%
10%=10/100=1/10
1/10 times 24=2.4
Homework: 2.4 hours


Free Time=15%
15%=15/100=3/30
3/20 times 24=72/20=36/10=3.6
Free Time: 3.6 Hours

Answers:
School: 6 hours
Eating: 2.4 hours
Sleep: 9.6 hours
Homework: 2.4 hours
Free Time: 3.6 Hours


Lines a and b are parallel. Line c is a transversal. Find the measures of all angles formed by a, b, and c, One of the angles is 70° bigger than the other

Answers

Answer:

Angles are either 55° or 125°.

Step-by-step explanation:

See the attached diagram.

Let aa' and bb' are two parallel straight lines and cc' is a transversal that meets aa' at o and bb' at o' points.

Now, ∠coa' + ∠coa =180° ..... (1)

Assume by the condition given ∠coa' = x and ∠coa = x+70

Hence, from equation (1), 2x + 70 = 180

x = 55°

Then ∠coa' =55° and ∠coa = 70+55 = 125°

So, ∠o'oa' = 125° as ∠coa = ∠ o'oa' {Opposite angles}

Again, ∠aoo' = 55° as ∠coa' = ∠aoo' {Opposite angles}

Now, ∠coa' = ∠oo'b' {Corresponding angles} = 55°

and ∠bo'c' = ∠oo'b' = 55° {Opposite angles}

Again ∠oo'b = ∠coa = 125° {Corresponding angles}

and ∠b'o'c' = ∠oo'b =125° {Opposite angles}

(Answer)

Answer:

The 4 angles formed in each case are: 55^(0), 55^(0), 125^(0) and 125^(0).

Step-by-step explanation:

Line c being transversal implies that it forms 4 angles with lines a and b individually of which 2 in each case are opposite angles, thus are equal.

Let one of the angles be represented by x^(0), but the other is greater by 70^(0), so that =  (70^(0) + x^(0))

Thus, we have;

    x^(0) + x^(0) + (70^(0) + x^(0)) + (70^(0) + x^(0)) = 360^(0)    ( the sum of angles at a point)

     x^(0) + x^(0) + 70^(0) + x^(0) + 70^(0) + x^(0) = 360^(0)

4x^(0)  +  140^(0) = 360^(0)

4x^(0) = 360^(0) - 140^(0)

4x^(0) = 220^(0)

Divide both sides by 4,

x^(0) = 55^(0)

The other angle is calculated thus,

   (70^(0) + x^(0)) = 70^(0) + 55^(0)

                 = 125^(0)

Thus the 4 angles formed in both cases have the values; 55^(0), 55^(0), 125^(0) and 125^(0).

Hasan wants to make an art design with an area of 50 square centimeters. If he males his design on centimeter grid paper,how many squares would the design cover? Tell how you know.

Answers

50 squares.

If Hasan is using a centimeter grid paper, then 50cm² means 50 little 1cm² squares :)
i am pretty sure the answer is 50 
i really hope i heled you out in some type of way :) 

What is the lateral area of a rectangular prism with length of 4in width of 5in and height of 15in

Answers

300 cubic in. I think

The distance between -12 and -5 on a number line?

Answers

On a number line, there are 7 spaces between -12 and -7.
7, There are 7 spaces between the two numbers on the line. 

Drag each angle measure to the correct location on the image. Each angle measure can be used more than once.In the figure, two parallel lines are cut by a transversal. One of the angles is labeled. Find the measures of the other angles and label them.
137°
117°
43°
53°

Answers

  1. Angle opposite the given angle: 137°
  2. - Angle adjacent to the given angle on the right: 43°
  3. - Angle adjacent to the given angle on the left: 43°
  4. - Angle opposite the angle adjacent to the given angle on the left: 137°

To find the measures of the other angles in the figure, let's start by labeling the given angle as 137°.

Since the two lines are parallel and a transversal cuts them, we know that corresponding angles are congruent

Therefore, the angle opposite the given angle will also measure 137°. Now, let's label the remaining angles. Let's consider the angle formed by the transversal and the line on the right. Since it is adjacent to the angle measuring 137°, their measures will add up to 180° (forming a straight line).

Therefore, the measure of this angle is 180° - 137° = 43°. Next, let's consider the angle formed by the transversal and the line on the left. Again, it is adjacent to the angle measuring 137°, so their measures will also add up to 180°.

Therefore, the measure of this angle is also 180° - 137° = 43°. Lastly, we have the remaining angle formed by the transversal and the line at the bottom.

Since it is opposite the angle measuring 137°, its measure is also 137°.

To summarize: - Angle opposite the given angle: 137° - Angle adjacent to the given angle on the right: 43° - Angle adjacent to the given angle on the left: 43° - Angle opposite the angle adjacent to the given angle on the left: 137°

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Answer:

I took the test in Edmentum and I git 5 correct

Step-by-step explanation:

I hope this help